正则表达式匹配-方括号内的内容

Question

This is a fast question, I just don't know many Regex tricks and can't find documentation for this exact point:

Lets say I have the string:

'I know [foo] and [bar] about Regex'

I want to do a JS Regex pattern that makes an array of each bracket encapsulation. Result:

['[foo]', '[bar]']

I currently have:

str.match(/\[(.*)\]/g);

But this returns:

'[foo] and [bar]'

Thanks.

Answer 1

str.match(/\[(.*?)\]/g);

Use a ? modifier to make the * quantifier non-greedy. A non-greedy quantifier will match the shortest string possible rather than the longest, which is the default.

Answer 2

Use this instead:

var str = 'I know [foo] and [bar] about Regex';
str.match(/\[([^\[\]]*)\]/g);

Your regex is partially wrong because of (.*) , which makes your pattern to allow any character between [ and ] , which includes [ and ] .

Answer 3

尝试

var array = 'I know [foo] and [bar] about Regex'.match(/(\[[^\]]+\])/g)

Answer 4

Use this instead:

\\[[^\\]]+\\]

Your regex is partially wrong because of (.*) , which makes your pattern to allow any character between [ and ] , which includes [ and ] .