[英]SQL Ordering Data from row “n+1” to “n-1”
I have a simple question. 我有一个简单的问题。 In MySQL, consider a row "n", how can we order rows by id (for example), but start from the row "n+1" and end to the row "n-1" ? 在MySQL中,考虑行“ n”,我们如何按ID对行进行排序(例如),但如何从行“ n + 1”开始到行“ n-1”呢?
Thanks ! 谢谢 !
EDIT : I ommit to precise that I seek the query in MySQL. 编辑:我省略精确地我在MySQL中查找查询。
From an answer below, here an example : 从下面的答案,这里是一个例子:
ID
---
1
2
3
4 <--N
5
6
I want Desired Results ordered as follows 我希望按以下顺序排序所需的结果
5 <--N + 1
6
1
2
3 <--N - 1
So you mean. 所以你的意思是 For a table 一张桌子
ID
---
1
2
3
4 <--N
5
6
You want Desired Results ordered as follows? 您要按以下顺序订购所需结果吗?
5 <--N + 1
6
1
2
3 <--N - 1
If so 如果是这样的话
SELECT ID
FROM T
WHERE ID <> 4
ORDER BY CASE WHEN ID > 4 THEN 0 ELSE 1 END, ID
Assuming table MyTable
with integer column N
: 假设表MyTable
的整数MyTable
N
:
SELECT *
from MyTable
where Id between N-1 and N+1
order by N desc
You're asking how to sort by descending ? 您在问如何按降序排序?
Just stick 只是坚持
ORDER BY col a , col b DESC;
at the end 在末尾
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