Regex.Replace用匹配的字符串替换

Question

I would like to compactly insert a <br /> tag before every line break in a string with regular expressions in C#. Can this be done? Currently, I am only able to replace the line break with the following:

myString = Regex.Replace(myString, @"\r\n?|\n", "<br />");

Can I modify this to include the matched text (ie either \\r\\n , \\r , or \\n ) in the replacement?

Clearly, it can be done with a separate Match variable, but I'm curious if it can be done in one line.

Answer 1

使用括号捕获换行符，并使用$1使用替换中捕获的内容：

myString = Regex.Replace(myString, @"(\r\n?|\n)", "<br />$1");

Answer 2

MSDN has a separate page just for .NET's regex substitution magic .

While the others are correct that the most general approach is to capture something and write back the captured contents with $n (where n is the captured group number), in your case you can simply write back the entire match with $& :

myString = Regex.Replace(myString, @"\r\n?|\n", "<br />$&");

If you are doing this a lot then avoiding the capturing could be a bit more efficient.

Answer 3

你可以用做替代在“替换”字符串：

Regex.Replace(myString, @"(\r\n?|\n)", "$1<br />");