如何在PHP中设置正则表达式

Question

I would like to know how to get the regular expression of the following text:

XXXXXX[Some Same Text # AAAA-NNNN]XXXXXX

Where:

'X' can vary any text: Alfa, numerical or symbols (The X can have 0 to infinite characters and it is NOT obligatory).
'A' Alfa uppercase text (The Alfa has exactly 4 uppercase letters and it is obligatory).
'N' Numbers (The N have exactly 4 numbers and it is obligatory).
'Some Same text' has exactly the same text always and it is obligatory.
'[,],#,-' will always be there in that same possition and it is obligatory.

I have a preg_match that goes:

*[Some Same Text([A-Z]{4})-([0-9]{4})]*

And it isn't seem to be working.

Thanks and regards!

Answer 1

. matches any character, and * means 0..infinity. When using [ and ] you need to escape them. Try this:

.*\[Some Same Text # ([A-Z]{4})-([0-9]{4})\].*

Answer 2

This should work: '/^.*\\[Some Same Text\\s#\\s[AZ]{4}-\\d{4}\\].*$/' . As Tested:

if(preg_match('/^.*\[Some Same Text\s#\s[A-Z]{4}-\d{4}\].*$/', 'XXXXXX[Some Same Text # AAAA-4444]XXXXXX'))echo 1;