C-检查字符串中的char是否属于数组

Question

Basically what I'm trying to do is that when a user inputs a string, my code will check the characters one by one and see if they belong to an array or not.

For instance i have an array:
char example[] = { 'a', 'b', 'c', 'd', 'e' };

And let's say the user inputs a string "example string" Now i want to check every single character individually in the string if they exist in the given array. So the first letter "e" clearly is in the array and whereas the letter "x" doesn't exist in the given array. So far I'm trying to use a loop and the memchr, but it just won't work for some reason, here is my code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(){
    char array[] = { 'a', 'b', 'c', 'd', 'e' };
    char input[40]; /*Reserved for the string*/
    int lengthofstring,i;
    scanf("%[^\n]s",input); /*This enables spaces in the input, and let's say 
    the string in this case is "example"*/
    lengthofstring=strlen(input);
    for (i=0;i<lengthofstring;i++){
        if (memchr(array,input[i],sizeof(array)){
            /* Now in this example input[i]="e", when i=0 and sizeof(array)=5*/
            printf("The letter %c does exist\n",input[i]);
        }
        else {
            printf("The letter %c does NOT exist\n",input[i]);
        }
    }
}

I'm really having a hard time to figure out what is wrong with this code, it always ends up in the does NOT exist category for some reason. Any advice or help is really appreciated, thanks in advance.

Answer 1

Code seems to be working for me. I did edit the code in the question, I may have unintentionally removed the problem. Please feel free to re-edit and post the original code, I can't seem to rollback my edit.

Working:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(){
    char array[] = { 'a', 'b', 'c', 'd', 'e' };
    char input[40]; /*Reserved for the string*/
    int lengthofstring,i;
    scanf("%[^\n]s",input); /*This enables spaces in the input, and let's say 
    the string in this case is "example"*/
    lengthofstring=strlen(input);
    for (i=0;i<lengthofstring;i++){
        if (memchr(array,input[i],sizeof(array))) {
            /* Now in this example input[i]="e", when i=0 and sizeof(array)=5*/
            printf("The letter %c does exist\n",input[i]);
        }
        else {
            printf("The letter %c does NOT exist\n",input[i]);
        }
    }
}

My additions, 2 closing } and a closing ) on the if statement

Original code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(){
char array[] = { 'a', 'b', 'c', 'd', 'e' };
char input[40]; /*Reserved for the string*/
int lengthofstring,i;
scanf("%[^\n]s",input); /*This enables spaces in the input, and let's say 
the string in this case is "example"*/
lengthofstring=strlen(input);
for (i=0;i<lengthofstring;i++){
if (memchr(array,input[i],sizeof(array)){
/* Now in this example input[i]="e", when i=0 and sizeof(array)=5*/
printf("The letter %c does exist\n",input[i]);}
else {
printf("The letter %c does NOT exist\n",input[i]);}