从ASPX的代码后面的用户控件中显示/隐藏模态弹出窗口

Question

I need to show/hide a reusable modal popup that it is in a UserControlWeb (ascx).

In my ASPX web, I defined the UC:

<%@ Register TagPrefix="uc" TagName="uc1" Src="~/Controls/modalpopup.ascx" %>
<uc:uc1 ID="ModalPopup1" runat="server" />

I can show/hide the modalpopup with javascript:

$find('MBehavior').show();
$find('MBehavior').hide();

But, I need to do from behind code of my ASPX web.

It is posible?

Answer 1

Try the above

 string script = @"  <script type=""text/javascript""> 
                  $find('MBehavior').show();
                });</script>";
            ClientScript.RegisterStartupScript(Page.GetType(), "", script);

Answer 2

如果页面中有updatepanel，则可以尝试；

ScriptManager.RegisterStartupScript(updatePanelID, updatePanelID.GetType(), Guid.NewGuid().ToString(), "$find('MBehavior').show(); $find('MBehavior').hide();", true);

Answer 3

if you want to to run from aspx:

$("#mybutton").click(function(e) {
      $find('MBehavior').show();
      $find('MBehavior').hide();
      e.preventDefault();
    });

if from code behind:

$("#mybutton").click(function(e) {
$.ajax( {
type:'Get',
url:'aspxfilename/mymethod',
success:function(data) {

}

});
e.preventDefault();
});

and in .cs file create a method:

[WebMethod]
public static string mymethod()
{
//run javascript
}