从'void *'到'void *（*）（void *）'c ++的无效转换？

Question

I am trying to use pthread_create() but it always gives me this error invalid conversion from void* to void* ( * )(void*)

This error is in the 3rd argument. Could someone help me with this error ?

void Print_data(void *ptr) {
    cout<<"Time of Week = " <<std::dec<<iTOW<<" seconds"<<endl;
    cout<<"Longitude = "<<lon<<" degree"<<endl;
    cout<<"Latitude  = "<<lat<<" degree"<<endl;
    cout<<"Height Above Sea = "<<alt_MSL<<" meters"<<endl;    
  }

int call_thread() 
  {
    pthread_create(&thread, NULL, (void *) &Print_data, NULL);
    return 0;
  }

Answer 1

The error is that you're converting the function pointer ( void* (*)(void*) ) to an object pointer ( void* ), when pthread_create expects a function pointer for that argument. There's no implicit conversion to undo the dodgy conversion you've done, hence the error.

The answer is to not do that:

pthread_create(&thread, NULL, &Print_data, NULL);

and you'll also need to modify Print_data to return void* to match the Posix threads interface:

void *Print_data(void *ptr) {
    // print stuff
    return NULL;  // or some other return value if appropriate
}

As noted in the comments, there are various other issues with using this C library directly from C++; in particular, for portability, the thread entry function should be extern "C" . Personally, I'd recommend using the standard C++ thread library (or Boost's implementation, if you're stuck with a pre-2011 version of the language).

Answer 2

You're trying to convert a function pointer into a void* here: (void *) &Print_data

According to pthread_create you need to pass in a function that takes a void* and returns a void*

So your function signature should be

void* Print_data(void *ptr) 

And your call should be

pthread_create(&thread, NULL, &Print_data, NULL);

Answer 3

pthread_create takes the third argument as

int pthread_create(pthread_t *thread,
                   const pthread_attr_t *attr,
                   void *(*start_routine)(void*),
                   void *arg);

This, void *(*start_routine)(void*) is a pointer to a function that takes a void* pointer and returns a void* pointer.

When you do &Print_data and convert the pointer to void * , it means you are passing a pointer of type void* and not a pointer of type void *(*start_routine)(void*) [function pointer].

To be correct, you need to make your return type as void* and make the call as pthread_create(&thread, NULL, &Print_data, NULL);

Answer 4

You must return void*

void* Print_data(void *ptr) {

to satisfy the needs.

The signature of the function to be passed is

void* function(void*);

then call pthread_create using

 pthread_create(&thread, NULL, &Print_data, NULL);

Answer 5

添加头文件#include并编译g ++ -lpthread