[英]Symfony2 entity choice issue
I have an entity
form field in my Symfony2 project. 我的Symfony2项目中有一个
entity
表单字段。
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('productId', 'genemu_jquerychosen_entity', array(
'class' => 'EMRSabaBundle:Product',
'property' => 'name'
))
;
}
The Product
entity has some objects like price, name, mode, & id I want to let user choose the product by name & see chosen produc's price, then submit product ID, not name. Product
实体具有一些对象,例如价格,名称,模式和ID,我想让用户按名称选择产品并查看所选产品的价格,然后提交产品ID,而不是名称。
Is there any soloution? 有什么东西吗?
As per the documentation for this bundle: 根据此捆绑包的文档:
You can use all the core choice types from Symfony (choice, country, ...) and Doctrine (ORM and ODM), you just have to prefix the type name with genemu_jqueryselect2_*
您可以使用Symfony(选择,国家,...)和主义(ORM和ODM)中的所有核心选择类型,只需在类型名称前加上genemu_jqueryselect2_ *
This means you are using a "regular" entity
field. 这意味着您正在使用“常规”
entity
字段。 You can do what you want by skipping the definition of property
and relying on the __toString()
method from EMRSabaBundle:Product
: 您可以通过跳过
property
的定义并依靠EMRSabaBundle:Product
的__toString()
方法来执行EMRSabaBundle:Product
:
[property]
[属性]
This is the property that should be used for displaying the entities as text in the HTML element.
这是用于在HTML元素中将实体显示为文本的属性。 If left blank, the entity object will be cast into a string and so must have a __toString() method.
如果保留为空白,则实体对象将转换为字符串,因此必须具有__toString()方法。
Change your code to: 将您的代码更改为:
$builder->add('productId', 'genemu_jquerychosen_entity', array(
'class' => 'EMRSabaBundle:Product'
))
And define the _toString()
method in your EMRSabaBundle:Product
object as follow: 并在
EMRSabaBundle:Product
对象中定义_toString()
方法,如下所示:
public function __toString()
{
return $this->name . ' (' . $this->price . ')';
}
http://symfony.com/doc/current/reference/forms/types/entity.html#property http://symfony.com/doc/current/reference/forms/types/entity.html#property
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