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如何从列表列表中删除一个级别的列表

[英]How to remove a level of lists from a list of lists

I have created some lists within a list and would like to be able have each sublist element to be an individual element at the top level.我在列表中创建了一些列表,并希望能够让每个子列表元素成为顶级的单个元素。

For example to create some dummy data:例如创建一些虚拟数据:

pp <- lapply(10:15,function(y){
    lapply(10:20,function(z){
        as.data.frame(matrix(rnorm(z*y),nrow=z,ncol=y))
    })  
})

This creates the following output这将创建以下输出

> summary(pp)
     Length Class  Mode
[1,] 11     -none- list
[2,] 11     -none- list
[3,] 11     -none- list
[4,] 11     -none- list
[5,] 11     -none- list
[6,] 11     -none- list

where you can also do你还可以在哪里做

> summary(pp[[1]])
      Length Class      Mode
 [1,] 10     data.frame list
 [2,] 10     data.frame list
 [3,] 10     data.frame list
 [4,] 10     data.frame list
 [5,] 10     data.frame list
 [6,] 10     data.frame list
 [7,] 10     data.frame list
 [8,] 10     data.frame list
 [9,] 10     data.frame list
[10,] 10     data.frame list
[11,] 10     data.frame list

The resultant output would just create a new list which has something like the below:结果输出只会创建一个新列表,其中包含如下内容:

new.pp[[1]] <- pp[[1]][[1]]
new.pp[[2]] <- pp[[1]][[2]]

but was wondering if there was a smart or more efficient method of just removing one level of lists when you have lists within lists....但是想知道是否有一种智能或更有效的方法可以在列表中有列表时只删除一级列表....

Ideally what I am looking for is some sort of function that carries this out for me, so that, if for example i had multiple levels of lists nested inside each other rather than just two, I can re-cursively use the function at each level bringing each element to the top of the list eventually...理想情况下,我正在寻找的是某种为我执行此操作的函数,因此,例如,如果我有多个级别的列表相互嵌套而不是两个,我可以在每个级别递归使用该函数最终将每个元素带到列表的顶部......

我认为这可以解决问题

new.pp <- unlist(pp,recursive=FALSE)

Tidyverse approach: Tidyverse 方法:

library(purrr)
new.pp <- flatten(pp)

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