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是否有可能在reify宏的splice部分内使用某些值?

[英]Is it possible to capture some value for use inside of `splice` part of `reify` macro?

For example, I have some list and want to iterate on it, and do macro transformation on each value: 例如,我有一些列表,想要对其进行迭代,并对每个值进行宏转换:

reify {
  someIntListExpr.splice.foreach { i =>
    // transform is a macro of the form 'transform(c: Context)(i: c.Expr[Int]): c.Expr[Unit]
    transform(i).splice
  }
}

But the compiler spits out error message: 但是编译器吐出错误消息:

found: Int
required: c.universe.Expr[Int]

Is there a way to fix it? 有办法解决吗?

In simple cases this will do the trick: 在简单的情况下,这可以解决问题:

someIntListExpr.splice.foreach { i =>
  transformImpl(c)(c.Expr[Int](Ident(newTermName("i")))).splice
}

Alternatively you can create method like this 或者,您可以创建这样的方法

def trans(i: Int): Unit = macro transform

and apply it: 并应用:

reify {
  someIntListExpr.splice.foreach { i =>
    trans(i)
  }
}

Sometimes you can actually get List[c.Expr[Unit]] . 有时您实际上可以得到List[c.Expr[Unit]]

If your method ( def myMethod(l: List[Int]): unti = macro myMethodImpl ) is called like myMethod(List(1, 2, x)) then you can get List[c.Expr[Unit]] : 如果像myMethod(List(1, 2, x))那样调用您的方法( def myMethod(l: List[Int]): unti = macro myMethodImplmyMethod(List(1, 2, x))则可以获取List[c.Expr[Unit]]

def myMethodImpl(c: Context)(l: c.Expr[List[Int]]): ... = {
  import c.universe.Apply
  val es = l match {
    case Apply(_, l: List[c.Expr[Int]]) => l
  }
  ...
}

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