[英]Python sqlite3 error
def menuAdiciona():
nome = input("Digite o nome de quem fez o cafe: ")
nota = int(input("Que nota recebeu: "))
if len(str(nome).strip()) == 0:
menuAdiciona()
if (nota) == 0:
menuAdiciona()
if nota < 0:
nota = 0
appears this: 出现此:
Can't convert 'int' object to str implicitly 无法将'int'对象隐式转换为str
First, the code you provided "works" in Python 2.7 and 3. 首先,您提供的代码在Python 2.7和3中“有效”。
A line number or stacktrace would be helpful, but assuming it's in the snippet you provided: 行号或堆栈跟踪会很有帮助,但是假设它在您提供的代码段中:
nota = int(input("Que nota recebeu: "))
Here nota
is an int. 这里nota
是一个int。
if len(str(nome).strip()) == 0:
The next line you're trying to cast it to a string without specifying how. 您尝试将其下一行强制转换为字符串而不指定方式。
Something like: 就像是:
if len(("%d" % nota).strip()) == 0:
should prevent the error. 应该防止错误。
That being said, the line still makes little sense. 话虽如此,这条线仍然没有意义。 You shouldn't have to strip()
a string representation of an integer. 您不必strip()
一个整数的字符串表示形式。
What are you trying to accomplish with strip()
and the if len(...) == 0
parts? 您要使用strip()
和if len(...) == 0
部分来完成什么工作?
Edit: Lastly, I think you want raw_input()
instead of input()
, unless you're shadowing that somewhere too. 编辑:最后,我认为您想要raw_input()
而不是input()
,除非您也将其隐藏在某个地方。
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