用于java.util.concurrent.Future的scala.concurrent.Future包装器

Question

I'm using Play Framework 2.1.1 with an external java library that produces a java.util.concurrent.Future result. I'm using the scala future's as opposed to Akka which I think is the right thing to do as of Play 2.1. How can I wrap the java.util.concurrent.Future up into a scala.concurrent.Future while still keeping the code non-blocking?

def geConnection() : Connection = {
  // blocking with get
  connectionPool.getConnectionAsync().get(30000, TimeUnit.MILLISECONDS)
}

The above code returns a connection but uses a get so it becomes blocking

def getConnectionFuture() : Future[Connection] = {
  future {
    // how to remove blocking get and return a scala future?
    connectionPool.getConnectionAsync().get(30000, TimeUnit.MILLISECONDS)
  }
}

Ideally I want a scala function that returns the connection as a future like the code above but without the code blocking via the get. What else do I need to put into the function to make it non blocking.

Any pointers would be great.

Answer 1

import java.util.concurrent.{Future => JFuture}
import scala.concurrent.{Future => SFuture}

You can't wrap JFuture with SFuture without blocking since there is a callback in SFuture ( onComplete ) and there is only blocking get in JFuture .

All you can do is to create additional thread and block it with get , then complete Promise with result of get .

val jfuture: JFuture[T] = ???
val promise = Promise[T]()
new Thread(new Runnable { def run() { promise.complete(Try{ jfuture.get }) }}).start
val future = promise.future

You could check isDone in endless loop, but I don't think it is better then blocking.

Answer 2

Future {
  blocking {
    jfuture.get
  }
}

This lets the ExecutionContext know that what you are doing is going to block, giving it a chance to allocate more threads. If you do not include blocking { } then you may run out of threads.

Answer 3

     import java.util.concurrent.{Future => JFuture}
     import scala.concurrent.ExecutionContext.Implicits.global
     import scala.concurrent.Future
     import scala.util.Try

     object JFuture2SFuture {
        val jFuture: JFuture[Int] = ???
        val promise = Promise[Int]()
        Future { promise.complete(Try(jFuture.get)) } //it is non blocking 
        val sFuture:Future[Int] = promise.future

     }

Answer 4

The scala-java8-compat library provides converters between java8 and Scala Futures.

Specifically, you can use FutureConverters.toScala(connectionPool.getConnectionAsync()) to convert the java.util.concurrent.Future to scala.concurrent.Future