如何使用ksh93从数组中的元素中提取项目？

Question

I have the following file

acc1:server1:server2:acc1234:blah:blah
acc2:server1:server5:acc4321:blah:blah
acc3:server1:server3:acc2222:blah:blah

Each line of the above file is an element in an array. I only need to get the first three items so accX:serverX:serverX .

How can I pull out only the first three items of each element without the ":" using ksh93?

Thanks!

Answer 1

Does this work for you:

$ set -A myarr acc1:server1:server2:acc1234:blah:blah acc2:server1:server5:acc4321:blah:blah acc3:server1:server3:acc2222:blah:blah

$ $ for ele in ${myarr[@]}; do ele=${ele%:*:*:*}; echo ${ele//:/ }; done
acc1 server1 server2
acc2 server1 server5
acc3 server1 server3

Answer 2

     #!/bin/ksh

     file=~/kshinput.txt
     index=0

     while read line
     do
            myarray[$index]=${line%:*:*:*}
            ((index=index+1))
     done <"$file"


     for i in {0..$index}
     do
            echo "$i: ${myarray[$i]}"
     done