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从文件中读取列表

[英]Reading a list from a file

I want to read from a .txt file, which has data saved as in list format. 我想从.txt文件中读取文件,该文件的数据另存为列表格式。

['http://www.example.com/?date=20080301',
 'http://www.example.com/?date=20080302',
 'http://www.example.com/?date=20080303']

I have the following code: 我有以下代码:

with open("test.txt", 'r') as file_name:
    for urls in file_name:
        for url in eval(urls):
            print url

It worked well with exactly idential file (only different links) and now out of a sudden, it raises an exception: 它与完全相同的文件(仅不同的链接)一起使用时效果很好,但突然之间,它引发了一个异常:

File "<string>", line 1
    ['http://www.example.com/?date=20080301',
                                            ^
SyntaxError: unexpected EOF while parsing

Do you have any ideas? 你有什么想法?

Use ast.literal_eval() : 使用ast.literal_eval()

import ast
with open("test.txt", 'r') as file_name:
    lists = ast.literal_eval(file_name.read())
    for url in lists:
        print url

It's much more efficient than using eval because, and quoting from the docs, it "safely evaluate[s] an expression node or a string containing a Python expression." 它比使用eval更为有效,因为并引用了文档,它“安全地评估表达式节点或包含Python表达式的字符串”。

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