从ASP.NET MVC中的其他模型表访问字段

Question

I have a page that displays a filtered table based on the user that is passed to the page. I also want to display the user's info a the top of the page, but this comes from a different table (from the Account model). Is there a way I can access fields from this table while working in my other controller/views?

Here is my code:

@{
    ViewBag.Title = "User Profile";
}

@model IEnumerable<FTv2.Models.Trade>

@{
    ViewBag.Title = "Active Trades";
    ViewBag.ImgUrl = ViewBag.Name + ".png";
}


<h2>@ViewBag.User's Profile:</h2>
<p>
    // This is where I would like to put the User info.
</p>
<h2>Active Trades:</h2>
<p>

</p>
<table>
    <tr>
        <th>
        </th>
        <th>
            @Html.DisplayNameFor(model => model.Name)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.Price)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.User)
        </th>
        <th></th>
    </tr>

@foreach (var item in Model)
{
    if (item.User == ViewBag.User)
    {
    <tr>
        <td>
            @{ViewBag.ImgUrl = @item.Name + ".png";}
        <a href="/Images/@ViewBag.ImgUrl"><img src="/Images/@ViewBag.ImgUrl" HEIGHT="66" WIDTH="50" ></a>
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Name)
        </td>
        <td>
            @Html.DisplayFor(modelItem => item.Price) TE
        </td>
        <td>
            <a href="/ActiveTrades/@item.User">@Html.DisplayFor(modelItem => item.User)</a>
        </td>
        @{if (ViewBag.User == User.Identity.Name){
        <td>
            @Html.ActionLink("Edit", "Edit", new { id = item.ID }) |
            @Html.ActionLink("Details", "Details", new { id = item.ID }) |
            @Html.ActionLink("Delete", "Delete", new { id = item.ID })
        </td>
        }}
    </tr>
    }
}

</table>

Answer 1

There are two options that I can think of:

1. Render an action method that returns the user details

   @{

    Html.RenderAction("UserDetails", new { UserID = ViewBag.UserID}); 

   }

2. Create a new model that has the user details plus an IEnumerable of the trades and use this for your view.

Answer 2

I suppose that you wanna

• make page model that will contain the User Info and IEnumerable<...> .
• or pass User info into ViewBag
• or call @Html.RenderAction()

I think that you need to keep in mind the chance of reuse of the view model class. If you see no way to reuse the model then use ViewBag to pass the info into a View. In the Controller's Action set the property ViewBag.UserInfo = userInfo; and in the view call: code @Html.Partial("_UserInfo", (UserInfo)ViewBag.UserInfo) code . But more practical way is to call @Html.Action(): 1. Make action UserController.UserInfo(int id). 2. Call from your view @Html.Action("UserInfo", "User", new {Id = ViewBag.UserId}); 3. create partial view for the UserController.UserInfo action.