SQL获取每个唯一ID的第一行以及在第一个后的x时间内具有该ID的每一行

Question

I was wondering if it is possible to have a single SQL command that returns each unique userID from a table as well as the rows containing that userID within the next 24 hours.

So for example I may have a table structured like:

id | userID | action | date

with a bunch of rows with thousands of unique userIDs, dozens of different actions, and dates. I am basically interested in what actions each userID does within the first 24 hours, but this for all users.

So I should get maybe 10-15 different actions for each userID, and each userID will be signing up on different days, months, or even years so it's not just grabbing all actions over a specific 24 hour period.

Answer 1

If I understand your question correctly, you could use a query like this:

SELECT a1.*
FROM
  actions a1 INNER JOIN (SELECT   userID, MIN(date) first_action
                         FROM     actions
                         GROUP BY userID) a2
  ON a1.userID = a2.userID AND a1.date <= first_action + INTERVAL 24 HOUR

Please see fiddle here . This query will return all actions that each user does in the first 24 hours after their first action.