[英]Construct File Path using Java
I am trying to create a file, but file path is constructed through String Concats that uses some internal variables and labels, I am getting following error : 我正在尝试创建文件,但是文件路径是通过使用一些内部变量和标签的String Concats构造的,出现以下错误:
Exception in thread "main" java.io.IOException: The filename, directory name, or volume label syntax is incorrect
at java.io.WinNTFileSystem.createFileExclusively(Native Method)
at java.io.File.createNewFile(Unknown Source)
at CopyEJ.CopyEJ.main(CopyEJ.java:133)
Is there a standard approach to built such files ? 是否有构建此类文件的标准方法?
String s_path = text_dir + "\\" + time_stmp + "_" + "Session" + "_" + file_name;
File ssw = new File(s_path);
ssw.createNewFile(); //Errors Out here
This will help you: 这将帮助您:
String path = "D://abc" + filename+ ".txt";
System.out.println("Path--- " + path);
File file = new File(path);
file.createNewFile()
You need to create the folder ( directory ) first: 您需要首先创建文件夹( directory ):
String s_path = text_dir + "/" + time_stmp + "_" + "Session" + "_" + file_name;
File ssw = new File(s_path);
ssw.getParentFile().mkdirs();
ssw.createNewFile();
If You are using Java 1.7 you can rewrite it as follows: 如果您使用的是Java 1.7,则可以按以下方式重写它:
Path s_path = Paths.get(text_dir, time_stmp + "_" + "Session" + "_" + file_name);
Files.createDirectories(s_path.getParent());
File ssw = s_path.toFile();
ssw.createNewFile();
Paths.get()
will use default system path separator. Paths.get()
将使用默认的系统路径分隔符。
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