使用JQuery ajax替换div，而不替换内容

Question

Here's an example doc structure

<div>
    <div id="1" class="to-replace"></div>
    <div id="2" class="to-replace"></div>
    <div id="3" class="to-replace"></div>
</div>

What I want to do is replace #1 , for example, with whatever I retrieve from the ajax call (I'm not using JSON because the request is extremely small and it didn't seem worth it. Plus, the site is mostly for my personal use). I know I can use JQuery .load() to replace the contents, but there must be some easy way to replace the whole thing.

Answer 1

您可以使用replaceWith jquery函数替换元素：

    $("#1").replaceWith("bla");

Answer 2

$.get(url,function(data){
   $("#1").replaceWith(data);
}); 

where url is the url to whatever you want to get and data is the data that is returned