如何仅从SQL Server的XML列中检索日期大于今天的日期的行？

Question

I want to only return rows that have a date in the XML column after the current date in SQL Server. How can i do this?

The error i receive for the last line below is: XQuery [LB_Webinar.WebinarXML.exist()]: There is no function '{ http://www.w3.org/2004/07/xpath-functions }:GETDATE()'

(
   @Site varchar(10)
)

AS

WITH XMLNAMESPACES ('http://www.testsite.com/ClientWebinar' as lbx)

SELECT * FROM LB_Webinar 

WHERE

Site = @Site

AND

LB_Webinar.WebinarXML.exist('/lbx:CLIENT_WEBINAR/lbx:WEBINAR/lbx:WEBINARDATE > GETDATE()') = 1

XML Code:

<lbx:CLIENT_WEBINAR xmlns:lbx="http://www.testsite.com/ClientWebinar">
    <lbx:WEBINAR>
        <lbx:WEBINARDATE>6/18/2013 2:00:00 PM</lbx:WEBINARDATE>
    </lbx:WEBINAR>
</lbx:CLIENT_WEBINAR>

Answer 1

You can store today's datetime value in a variable and use sql:variable() in your expression to use the variable in the comparison.

DECLARE @Today DATETIME;
SET @Today = GETDATE();

WITH XMLNAMESPACES ('http://www.testsite.com/ClientWebinar' as lbx)
SELECT *
FROM LB_Webinar 
WHERE LB_Webinar.WebinarXML.exist('/lbx:CLIENT_WEBINAR/lbx:WEBINAR/lbx:WEBINARDATE/text()[. > sql:variable("@Today")]') = 1;

Note: the above code works if you change your datetime values to ISO8601 yyyy-mm-ddThh:mi:ss.mmm .