使用href获取父div

Question

Is is possible to find the parent div using just the href?

I basically have the following function:

var hrefs = [];
[].forEach.call(document.querySelectorAll("area"), function (value, index, array) {
    hrefs.push(value.getAttribute("href"));
});

for (var i = 0; i < hrefs.length; i++) {
    console.log(hrefs[i]);
    }

which finds all hrefs that belong to a html area. I am trying to find the parent element of these hrefs so that I can append a new div to that parents element. If this is not possible, what attribute would I need to be able to located the parent div of that attribute.

Answer 1

You want something like this?:

var hrefs = document.querySelectorAll("area");

for (var i = 0; i < hrefs.length; i++) {
    console.log(hrefs[i].getAttribute('href'));
    console.log(hrefs[i].parentNode);
}

Answer 2

First create an object with all those elements:

var hrefs = {};

Array.prototype.forEach.call(document.querySelectorAll("area[href]"), function (element) {
    hrefs[ element.getAttribute("href") ] = element;
});

Then you can get to their parent by using .parentNode :

for ( var i in hrefs ) {
    console.log( i, hrefs[i].parentNode );
}

---

So, if you want to later add an element to the parent of http://www.google.com , you could do this:

hrefs['http://www.google.com'].parentNode.appendChild( element );

Answer 3

I cannot see why you wouldn't just:

[].forEach.call(document.querySelectorAll("area"), function(area) {
    area.parentNode.appendChild(
        document.createElement("div")
    );
});

Answer 4

The strategy is to get all the area elements, then match on their href value. The following returns the first matching area element:

function getAreaByHref(href) {
  var areas = document.getElementsByTagName('area');
  for (var i = 0, iLen=areas.length; i<iLen; i++) {
    if (areas[i].href == href) {
      return areas[i].parentNode;
    }
  }
}

If you think there will be more than one, have the function build an array of matched elements and return that.

Answer 5

如果使用jQuery，则可以使用.parent（）方法来完成此操作。