在文件的每一行之后添加额外的行

Question

adding extra lines after each line in a file

I need help for the following task for around 1000 lines file.

INPUT

    ./create.pl     1eaj.out
    ./create.pl     1ezg.out
    ./create.pl     1f41.out
    ...

OUTPUT

    ./create.pl     1eaj.out
    mv complex.* 1eaj
    ./create.pl     1ezg.out
    mv complex.* 1ezg
    ./create.pl     1f41.out
    mv complex.* 1f41
    ...

I know following command can add the new line and first part which makes the output like below.

    awk ' {print;} NR % 1 == 0 { print "mv complex.*  "; }'

    ./create.pl     1eaj.out
    mv complex.* 
    ./create.pl     1ezg.out
    mv complex.* 
    ./create.pl     1f41.out
    mv complex.* 
    ...

How to do the rest? Thanks a lot in advance.

Answer 1

My attempt:

sed -n 's/^\(\.\/create\.pl\)\s*\(.*\)\.out$/\1 \2.out\nmv complex.* \2/p' s.txt

or using && between ./create.pl and mv (since mv is likely needed only when ./create.pl is correctly executed):

sed -n 's/^\(\.\/create\.pl\)\s*\(.*\)\.out$/\1 \2.out \&\& mv complex.* \2/p' s.txt

which gives:

./create.pl 1eaj.out && mv complex.* 1eaj
./create.pl 1ezg.out && mv complex.* 1ezg
./create.pl 1f41.out && mv complex.* 1f41

Answer 2

You were nearly there:

$ awk '{print $1, $2, "\nmv complex.*", $2}' file
./create.pl 1eaj.out 
mv complex.* 1eaj.out
./create.pl 1ezg.out 
mv complex.* 1ezg.out
./create.pl 1f41.out 
mv complex.* 1f41.out

Answer 3

使用空格或点作为分隔符以提取所需的单词：

awk -F '[[:blank:].]+' '{print; print "mv complex.*", $4}' filename