从视图将变量发送到控制器：Zend Controller

Question

I want to send a set of variables to the controller from the view , but apparently they don t come to the controller, already the success function does not repent, here is the code for sending the niveu of view, knowing that the success function m displays nothing :

$.ajax({ 

     type: "POST", 
     url: "<?php echo $this->url(array('controller' => 'properties', "action"      =>"tasktodo")); ?>",                  
      data: { 
      latitude: position.coords.latitude, 
      longitude: position.coords.longitude, 
      }, 
      success: function(data) { 
      alert ("datalatit"); 
      } 
      }); 

can someone tell me where is the problem ?

Answer 1

There could be several problems with your request:

1. Make sure that the url is generated correctly. Try via hardcoding it just to see. Also debug the output of: echo $this->url(array('controller' => 'properties",.....

2. As @Tim Fountain suggested check if you are sending data (Provided that your request gets through at all)

3. Check if there is something blocking your request? Security, Authentication, etc. ??

4. Implement the error callback of jQuery's $.ajax(); It is there to handle errors and any implementation of an AJAX call should have it. An example implementation that would "dump" all variables to the console is:

    success: function(data) {......}, error : function (jqXHR, textStatus, errorThrown){console.warn('An error occured!');console.log(jqXHR);console.log(textStatus);console.log(errorThrown);} 

This way you will be able to inspect the error. Then implement something to handle it.

Sorry for the poor format of the code. I had some problem with the editor here..