python：确定列表的所有条目是否在嵌套列表的条目内

Question

I have a nested list such as:

>>l = [[['bcsA', 'F'], ['bcsB', 'F'], ['bcsC', 'R']], [['bcsE', 'R'], ['bcsF', 'R']]]
>>n = [['GROUP A'], [[['bcsQ', 'F'], ['bcsA', 'F'], ['bcsB', 'F'], ['bcsZ', 'F'], ['bcsC', 'F']], [['yhjK', 'R']], [['yhjK', 'F']], [['bcsC', 'R'], ['bcsZ', 'R'], ['bcsB', 'R'], ['bcsA', 'R'], ['bcsQ', 'R']], [['bcsC', 'F'], ['bcsZ', 'F'], ['bcsB', 'F'], ['bcsA', 'F'], ['bcsQ', 'F']]]], 
      [[['GROUP A'], [[['bcsA', 'F'], ['bcsB', 'F'], ['bcsC', 'R']], [['bcsE', 'R'], ['bcsF', 'R']], [['yhjK', 'F']]]], 

So what I was hoping to do is if the nested lists [['bcsA', 'F'], ['bcsB', 'F'], ['bcsC', 'R']] and [['bcsE', 'R'], ['bcsF', 'R']] were found in the same list in the other nested list then it would give me the first entry.

the output would, hopefully, be GROUP B .

The list l will be different each time I go through the program.

I have tried a bunch of variations of:

>>>for x in n:
>>>    if all(e in x for e in l):
>>>         print n[n.index(x)][0] 

I think what it is doing is if the individual items in the nested list of l are anywhere in n then it will give me that they are in GROUP A but really the output should be GROUP B. I have tried it without the all() statement as well. I feel like this is a simple thing but I cannot figure it out. I hope this makes sense. Thank you for any help!

tl;dr: How to tell if all values of a list are contained within a nested list and if so, print the first entry of the nested list.

Answer 1

我认为应该记住， bool([False]) == True和bool([True]) == True因此在使用结构[any(...)]: ，任何人都可以肯定地说这句话会是True