PHP从用户名等于X的数据库中选择字段

Question

im having problems in PHP with selecting Infomation from a database where username is equal to $myusername

I can get it to echo the username using sessions from the login page to the logged in page.

But I want to be able to select things like 'bio' and 'email' from that database and put them into variables called $bio and $email so i can echo them.

This is what the database looks like:

Any ideas?:/

Answer 1

You should connect to your database and then fetch the row like this:

// DATABASE INFORMATION
$server = 'localhost';
$database = 'DATABASE';
$dbuser = 'DATABASE_USERNAME';
$dbpassword = 'DATABASE_PASSWORD';

//CONNECT TO DATABASE
$connect = mysql_connect("$server", "$dbuser", "$dbpassword")
    OR die(mysql_error());
   mysql_select_db("$database", $connect);
//ALWAYS ESCAPE STRINGS IF YOU HAVE RECEIVED THEM FROM USERS
$safe_username = mysql_real_escape_string($X);
//FIND AND GET THE ROW
$getit = mysql_query("SELECT * FROM table_name WHERE username='$safe_username'", $connect);
$row = mysql_fetch_array($getit);

//YOUR NEEDED VALUES
$bio = $row['bio'];
$email = $row['email'];

Note 1:

Dont Use Plain Text for Passwords, Always hash the passwords with a salt

Note 2:

I used MYSQL_QUERY for your code because i don't know PDO or Mysqli, Escaping in MYSQL is good enought but Consider Using PDO or Mysqli , as i don't know them i can't write the code with them for you

Answer 2

Simplistic PDO examples.

Create a connection to the database.

$link = new PDO("mysql:host=$db_server;dbname=$db_name", $db_user, $db_pw, array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"));
$link->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

Use the $link variable when creating (preparing) and executing your SQL scripts.

$stmt = $link->prepare('insert into `history` (`user_id`) values(:userId)');
$stmt->execute(array(':userId' => $userId));

Code below will read data. Note that this code is only expecting one record (with 2 data elements) to be returned, so I'm storing whatever is returned into a single variable (per data element), $webId and $deviceId .

$stmt = $link->prepare('select `web_id`, `device_id` from `history` where `user_id` = :userId');
$stmt->execute(array(':userId' => $userId));
while($row = $stmt->fetch()) {
    $webId = $row["web_id"];
    $deviceId = $row["device_id"];
}

Answer 3

From the picture I can see you are using phpMyAdmin - a tool used to handle MySQL databases. You first must make a connection to the MySql server and then select a database to work with. This is shown how below:

<?php
$username = "your_name"; //Change to your server's username
$password = "your_password"; //Change to your server's password
$database = "your_database" //Change to your database name
$hostname = "localhost"; // Change to the location of your server (this will prolly be the same for you I believe tho 

$dbhandle = mysql_connect($hostname, $username, $password)
  or die("Unable to connect to MySQL");
echo "Connected to MySQL<br>";

$selected = mysql_select_db($database, $dbhandle)
  or die("Could not select examples");
?>

Then you can write something like this:

<?php
$bio = mysql_query("SELECT bio FROM *your_database_table_name* WHERE username='bob' AND id=1");
?>

and

<?php
$email = mysql_query("SELECT email FROM *your_database_table_name* WHERE username='bob' AND id=1");
?>

Where *your_database_table_name* is the table in the database you selected which you are trying to query.

When I was answering your question, I was referencing this site: http://webcheatsheet.com/PHP/connect_mysql_database.php . So it might help to check it out as well.