[英]find whether the string starts and ends with the same word
I am trying to check whether the string starts and ends with the same word. 我试图检查字符串是否以相同的单词开头和结尾。 eg
earth
. 例如
earth
。
s=raw_input();
m=re.search(r"^(earth).*(earth)$",s)
if m is not None:
print "found"
my problem is when the string consists only of one word eg: earth
我的问题是当字符串只包含一个单词时,例如:
earth
At present I have hard coded this case by 目前我已经硬编码了这个案例
if m is not None or s=='earth':
print "found"
Is there any other way to do this? 有没有其他方法可以做到这一点?
EDIT: 编辑:
words in a string are separated by spaces. 字符串中的单词用空格分隔。 looking for a regex solution
寻找正则表达式解决方案
some examples
: some examples
:
"earth is earth" ,"earth", --> valid
“地球是地球”,“地球”, - >
valid
"earthearth", "eartheeearth", "earth earth mars" --> invalid
“earthearth”,“eartheeearth”,“earth earth mars” - >
invalid
Use the str.startswith
and str.endswith
methods instead. 请改用
str.startswith
和str.endswith
方法。
>>> 'earth'.startswith('earth')
True
>>> 'earth'.endswith('earth')
True
You can simply combine them into a single function: 您可以简单地将它们组合成一个函数:
def startsandendswith(main_str):
return main_str.startswith(check_str) and main_str.endswith(check_str)
And now we can call it: 现在我们可以称之为:
>>> startsandendswith('earth', 'earth')
True
If, however, if the code matches words and not part of a word, it might be simpler to split the string, and then check if the first and last word are the string you want to check for: 但是,如果代码匹配单词而不是单词的一部分,则拆分字符串可能更简单,然后检查第一个和最后一个单词是否是您要检查的字符串:
def startsandendswith(main_str, check_str):
if not main_str: # guard against empty strings
return False
words = main_str.split(' ') # use main_str.split() to split on any whitespace
return words[0] == words[-1] == check_str
Running it: 运行它:
>>> startsandendswith('earth', 'earth')
True
>>> startsandendswith('earth is earth', 'earth')
True
>>> startsandendswith('earthis earth', 'earth')
False
You can use backreference within regex 您可以在正则表达式中使用反向引用
^(\w+\b)(.*\b\1$|$)
This would match a string only if it 这只会匹配一个字符串
You can use str.startswith
and str.endswith
: 您可以使用
str.startswith
和str.endswith
:
>>> strs = "earthfooearth"
>>> strs.startswith('earth') and strs.endswith("earth")
True
>>> strs = "earth"
>>> strs.startswith('earth') and strs.endswith("earth")
True
Update: 更新:
If the words are separated by spaces and the start and end string is not known then use str.split
and str.rsplit
: 如果单词用空格分隔并且开始和结束字符串未知,则使用
str.split
和str.rsplit
:
>>> strs = "foo bar foo"
>>> strs.split(None, 1)[0] == strs.rsplit(None, 1)[-1]
True
# single word
>>> strs = "foo"
>>> strs.split(None, 1)[0] == strs.rsplit(None, 1)[-1]
True
>>> strs = "foo bar ffoo"
>>> strs.split(None, 1)[0] == strs.rsplit(None, 1)[-1]
False
Here: 这里:
X = words.split()
X[:1] == X[-1:]
The slicing makes it work for empty strings too, and extend nicely to any number of words. 切片使它也适用于空字符串,并可以很好地扩展到任意数量的单词。 If
words
cannot be empty, use 如果
words
不能为空,请使用
X[0] == X[-1]
Well, if you absolutely want regex, you can make use of lookarounds, since they don't consume characters. 好吧,如果你绝对想要正则表达式,你可以使用lookarounds,因为它们不消耗字符。
>>>import re
>>>s1 = 'earth is earth'
>>>s2 = 'earth'
>>>m = re.search(r"^(?=(earth)).*(earth)$",s1)
>>>m.group(1)
'earth'
>>>m.group(2)
'earth'
>>>m = re.search(r"^(?=(earth)).*(earth)$",s2)
>>>m.group(1)
'earth'
>>>m.group(2)
'earth'
For any string, you could perhaps use this: 对于任何字符串,您可以使用此:
^(?=([A-Za-z]+)).*(\1)$
I'm assuming words as being only alphabet characters. 我假设单词只是字母字符。 If you mean words as in non-space characters, then you may go for
\\S
instead of [A-Za-z]
. 如果你的意思是非空格字符,那么你可以去
\\S
而不是[A-Za-z]
。
EDIT: Okay, it seems there's more to it. 编辑:好的,它似乎还有更多。 What I think might suit is:
我认为可能适合的是:
^(?=(earth\b)).*((?:^|\s)\1)$
For the work earth. 为了工作地球。 For any word stored in a variable named
word
; 对于存储在名为
word
的变量中的任何word
;
>>> word = 'earth' # Makes it so you can change it anytime
>>> pattern = re.compile('^(?=(' + word + '\b)).*((?:^|\s)\1)$')
>>> m.search(pattern, s)
Accepts: 接受:
earth is earth
earth
Rejects: 拒绝:
earthearth
eartheearth
earthis earth
And after that extract the captured groups or check whether the group are empty or not. 然后提取捕获的组或检查组是否为空。
The bit I added is (?:^|\\s)
which checks for whether the word you're looking for is the only one in the 'sentence' or whether the word is in a sentence. 我添加的位是
(?:^|\\s)
,它检查您要查找的单词是否是“句子”中唯一的单词,或者单词是否在句子中。
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