php数组的总和（从mysql结果创建），具体取决于另一个mysql列中的mysql值

Question

One table called 18_7_ChartOfAccounts looks like this:

ID | AccountNumber
-------------
1  | 2310
2  | 2380
3  | 2610

Another table called 2_1_journal looks like this:

ID | Amount | DebitAccount
--------------------------
1  | 26.03  | 2310
2  | 200.00 | 2310
3  | 3.63   | 2380
4  | 119.83 | 2380
5  | 33.86  | 2610
6  | 428.25 | 2610

Aim is to get results that looks like this:

DebitAccount 2310 total is: 226.03
DebitAccount 2380 total is: 123.46
DebitAccount 2310 total is: 462.11

226.03 in this example is total of 26.03 + 200.00

At first mysql code

$query = "SELECT j.Amount, j.DebitAccount FROM 18_7_ChartOfAccounts AS c LEFT JOIN 2_1_journal AS j ON (c.AccountNumber = j.DebitAccount)";
$sql = $db->prepare($query);
$sql->execute();
$data = $sql->fetchAll(PDO::FETCH_ASSOC);

With print_r($data); get long list of arrays like

[31] => Array
    (
        [Amount] => 26.03
        [DebitAccount] => 2310

[32] => Array
    (
        [Amount] => 200.00
        [DebitAccount] => 2310

If in mysql query use SUM(j.Amount) then get only one total amount (suppose total amount of Column Amount ).

With

foreach($data as $result){
if(strlen($result['Amount']) > 0 ) {
echo "Amount ". $result['Amount']. "Account name ". $result['DebitAccount']. "<br>";
print_r (array_sum($result));
}
}

Get something like this

Amount 123.97Account name 2310
2433.97Amount 26.03Account name 2310
2336.03Amount 200.00Account name 2310

Any ideas how to get necessary results (marked bold)?

Update

Changed $query to

$query = "SELECT SUM(j.Amount), j.DebitAccount FROM 18_7_ChartOfAccounts AS c LEFT JOIN 2_1_journal AS j ON (c.AccountNumber = j.DebitAccount) group by j.DebitAccount";

with print_r($data); get array like this

Array
(
[0] => Array
    (
        [SUM(j.Amount)] => 
        [DebitAccount] => 
    )

[1] => Array
    (
        [SUM(j.Amount)] => 110900.16
        [DebitAccount] => 2310
    )

[2] => Array
    (
        [SUM(j.Amount)] => 3660.86
        [DebitAccount] => 2380
    )

With array seems all works. Now with foreach changed to echo "Amount ". $result['SUM(j.Amount)']. " Account name ". $result['DebitAccount']. "<br>"; echo "Amount ". $result['SUM(j.Amount)']. " Account name ". $result['DebitAccount']. "<br>";

Get

Amount 110900.16 Account name 2310
Amount 3660.86 Account name 2380
Amount 85247.40 Account name 2610

Seems also ok. Thanks

Answer 1

You are going about it wrong. You can get the sum through MySql statement itself.

Use the aggrgate function sum along with group by clause.

Like this,

SELECT DebitAccount,sum(Account) from  2_1_journal group by DebitAccount

Your full code:

$query = " SELECT DebitAccount,sum(Account) as Total from  2_1_journal group by DebitAccount";
$sql = $db->prepare($query);
$sql->execute();
$data = $sql->fetchAll(PDO::FETCH_ASSOC);
foreach($data as $result){
if(strlen($result['Total']) > 0 ) {
echo "DebitAccount ". $result['DebitAccount']. "Total is: ". $result['Total']. "<br>";
print_r (array_sum($result));
}
}

Answer 2

SELECT DebitAccount, SUM(Amount) 
FROM 2_1_journal 
GROUP BY DebitAccount

Answer 3

您必须在查询中使用GROUP BY

SELECT DebitAccount, SUM(Amount) AS Amount FROM 2_1_journal GROUP BY DebitAccount