[英]CTFontGetGlyphsForCharacters always returns false
Please help me understand the problem with the following code: 请帮我理解以下代码的问题:
NSString *fontName = @"ArialMT";
CGFloat fontSize = 20.0;
CTFontRef fontRef = CTFontCreateWithName((CFStringRef)fontName, fontSize, NULL);
NSString *characters = @"ABC";
NSUInteger count = characters.length;
CGGlyph glyphs[count];
if (CTFontGetGlyphsForCharacters(fontRef, (const unichar*)[characters cStringUsingEncoding:NSUTF8StringEncoding], glyphs, count) == false)
NSLog(@"*** CTFontGetGlyphsForCharacters failed.");
Any help is appreciated. 任何帮助表示赞赏。
You are getting a C string containing UTF-8 encoded characters and then casting it to unichar *
. 您将获得包含UTF-8编码字符的C字符串,然后将其转换为unichar *
。 That won't work. 那不行。 A unichar
is a 16-bit UTF-16-encoded character. unichar
是一个16位UTF-16编码字符。 A simple C cast won't convert the character encoding. 简单的C cast不会转换字符编码。
You need to ask the string for its characters as an array of unichar
: 你需要将字符串的字符作为unichar
数组来询问:
NSString *fontName = @"ArialMT";
CGFloat fontSize = 20.0;
CTFontRef fontRef = CTFontCreateWithName((CFStringRef)fontName, fontSize, NULL);
NSString *string = @"ABC";
NSUInteger count = string.length;
unichar characters[count];
[string getCharacters:characters range:NSMakeRange(0, count)];
CGGlyph glyphs[count];
if (CTFontGetGlyphsForCharacters(fontRef, characters, glyphs, count) == false)
NSLog(@"*** CTFontGetGlyphsForCharacters failed.");
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