如果使用preg_match进行换行，如何获取html内容？

Question

How to include the line-breaks in my regex when doing a preg_match of html source?

php

preg_match('/Корица:<\/b><\/td><td>(.*)<\/td>/im', $table[0], $korica);

html(also this is what is in $table[0] ):

<tr>

            <td><b>Година на издаване:</b></td>

            <td itemprop="datePublished">2009</td>

          </tr>

          <tr>

            <td><b>Корица:</b></td>

            <td>Мека</td>

          </tr>

          <tr>

            <td><b>Език:</b></td>

            <td itemprop="inLanguage">Български</td>

          </tr>





                      <tr>

            <td><b>Средна оценка:</b></td>

            <td>                  Продуктът няма оценка                  </td>

          </tr>

If i use preg_match_all i will get all the html after the Корица. But what i want is to get only this Meka from the html.

Answer 1

将正则表达式中的(.*)部分更改为非贪婪(.*?) ，甚至更好 - ([^<]*) ，它匹配所有非< 。

Answer 2

If "Meka" is always alphanumeric, then something like this might work:

    preg_match('/Корица:<\/b><\/td><td>([a-zA-Z0-9]*)<\/td>/im', $table[0], $korica);

[a-zA-Z0-9]* should match only alphanumeric characters. You might have to consider a space too, in which case you should use [a-zA-Z0-9 ]* (Notice the space before the closing ])