[英]Udp image streaming, delphi indy10
i'm using delphi xe4 with indy10 component and i want to send an image from an Tidudpclient to Tidudpserver. 我正在使用带有indy10组件的delphi xe4,我想将一个图像从Tidudpclient发送到Tidudpserver。 I already done this operation with tcp component,but the same code didn't work with udp. 我已经使用tcp组件完成了此操作,但相同的代码不能与udp一起使用。 how i can do this? 我怎么能这样做? Thanks in advance! 提前致谢!
Timage(client)--->streamUDP-->Timage(server) TImage中(客户端)---> streamUDP - >的TImage(服务器)
CLIENT SIDE----------------------------------------------- SEND IMAGE 客户端-----------------------------------------------发送图片
var
pic: tbitmap;
Strm : TMemoryStream;
img2:Timage;
buffer:TIdBytes;
begin
try
img2:=Timage.Create(nil);
pic:=Tbitmap.Create;
Takekpic(pic);
BMPtoJPG(pic,img2);
Strm := TMemoryStream.Create;
img2.Picture.bitmap.SaveToStream(strm);
Strm.Position:=0;
ReadTIdBytesFromStream(Strm,buffer,SizeOf(Strm),0);
IdTrivialFTPServer1.SendBuffer('192.168.17.128',1234,buffer);
finally
strm.Free;
end;
end;
SERVER SIDE---------------------------------------------------- READ IMAGE 服务器端 - - - - - - - - - - - - - - - - - - - - - - - - ----阅读图片
procedure TForm6.IdTrivialFTP1UDPRead(AThread: TIdUDPListenerThread;
const AData: TIdBytes; ABinding: TIdSocketHandle);
var
Strm : TMemoryStream;
Jpg: TJpegImage;
begin
Strm := TMemoryStream.Create;
try
WriteTIdBytesToStream(Strm,AData,SizeOf(AData),0);
strm.Position:=0;
Jpg := TJpegImage.Create;
jpg.LoadFromStream(Strm); <---- error while reading (JPEG Error #53)
img1.Picture.assign(jpg);
finally
strm.Free;
Jpg.Free;
end;
end;
what can be wrong in this code? 这段代码有什么不对吗?
TIdUDPClient
and TIdUDPServer
do not support sending/receiving TStream
data. TIdUDPClient
和TIdUDPServer
不支持发送/接收TStream
数据。 You can save your image data into a TStream
, but you will have to send/receive it using TIdBytes
chunks. 您可以将图像数据保存到TStream
,但必须使用TIdBytes
块发送/接收它。
Alternatively, use TIdTrivialFTP
and TIdTrivialFTPServer
instead, which implement TFTP, a UDP-based file transfer protocol. 或者,使用TIdTrivialFTP
和TIdTrivialFTPServer
来实现TFTP,这是一种基于UDP的文件传输协议。 They operate using TStream
objects 它们使用TStream
对象进行操作
Update : for example: 更新 :例如:
Client: 客户:
var
bmp: TBitmap;
jpg: TJPEGImage;
Strm : TMemoryStream;
begin
Strm := TMemoryStream.Create;
try
jpg := TJPEGImage.Create;
try
bmp := TBitmap.Create;
try
Takekpic(bmp);
jpg.Assign(bmp);
finally
bmp.Free;
end;
jpg.SaveToStream(Strm);
finally
jpg.Free;
end;
Strm.Position := 0;
{
These can be assigned ahead of time...
IdTrivialFTP1.Host := '192.168.17.128';
IdTrivialFTP1.Port := 1234;
}
IdTrivialFTP1.Put(Strm, 'image.jpg');
finally
Strm.Free;
end;
end;
Server: 服务器:
procedure TForm6.IdTrivialFTPServer1WriteFile(Sender: TObject; var FileName: String; const PeerInfo: TPeerInfo; var GrantAccess: Boolean; var AStream: TStream; var FreeStreamOnComplete: Boolean) of object;
begin
if FileName = 'image.jpg' then
begin
GrantAccess := True;
AStream := TMemoryStream.Create;
FreeStreamOnComplete := True;
end else
GrantAccess := False;
end;
{
If you set TIdTrivialFTPServer.ThreadedEvent to False, this event handler
runs in the context of the main thread, so the UI can be accessed safely.
If you set IdTrivialFTPServer.ThreadedEvent to True, this event handler
runs in the context of a worker thread, so you will have to manually
synchronize with the main thread when updating the UI...
}
procedure TForm6.IdTrivialFTPServer1TransferComplete(Sender: TObject; const Success: Boolean; const PeerInfo: TPeerInfo; var AStream: TStream; const WriteOperation: Boolean);
var
jpg: TJPEGImage;
begin
if WriteOperation and Success then
begin
jpg := TJPEGImage.Create;
try
AStream.Position := 0;
jpg.LoadFromStream(AStream);
img1.Picture.Assign(jpg);
finally
jpg.Free;
end;
end;
end;
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