[英]Cloning a <select> without one <option>
I have a select box with all european countries in there, the idea is that a person picks one or more countries that he/she does his/her business in. 我有一个选择框,其中包含所有欧洲国家/地区,其想法是一个人选择一个或多个在其开展业务的国家/地区。
This is how it looks right now: 现在是这样的:
And this is the javascript function: 这是javascript函数:
function AddCountry(element) {
var oldSelect = jQuery("select[name='investor-country[]']").last();
var newSelect = jQuery(oldSelect).clone();
jQuery(element).before(newSelect);
}
So when the person clicks on the Add country link, the javascript gets executed and another <select> is inserted above the link (the links is also the parameter being sent). 因此,当该人单击“添加国家/地区”链接时,将执行javascript并将另一个<select>插入到链接上方(链接也是要发送的参数)。 This is an exact copy of the one before.
这是之前版本的精确副本。 The thing is I want it to remove the previous selected company from the list so the user can not (without having HTML knowlegde) enter two of the same countries.
问题是我希望它从列表中删除以前选择的公司,以便用户不能(没有HTML知识)输入两个相同的国家。
I tried alot but haven't succeeded. 我尝试了很多,但没有成功。 I tried all kind of weird jQuery combinations but mainly:
我尝试了所有奇怪的jQuery组合,但主要是:
newSelect.remove(0);
As far as I could find this should remove the first option from the list (0 can be replace with selectedIndex later) but it doesn't! 据我发现,这应该从列表中删除第一个选项(0以后可以替换为selectedIndex),但事实并非如此!
function AddCountry(element) {
var oldSelect = jQuery("select[name='investor-country[]']").last();
var newSelect = jQuery(oldSelect).clone();
// Remove previously selected option
var selected = oldSelect.val();
newSelect.find("option[value="+selected+"]").remove();
jQuery(element).before(newSelect);
}
删除所选选项的另一种方法:
newSelect.find('option').eq(oldSelect[0].selectedIndex).remove();
Try this: 尝试这个:
//get the selected value
var val = $("select[name='investor-country[]']").val();
//get the selected option
var option = $("option[value="+val+"]");
//append the selected country somewhere
$('#selected').append('<span>'+option.text()+'</span> ');
//remove the selected option
option.remove();
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