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从xml元素中选择多个属性值,该属性具有与特定情况匹配的属性c#LINQ

[英]select multiple values of attributes from xml element which has an attribute matching the certain case c# LINQ

I have XML that looks like 我有看起来像的XML

<?xml version="1.0"?>
   <configuration>
      <TemplateMapper>
         <Template XML="Product.xml" XSLT="sheet.xslt" Keyword="Product" />
         <Template XML="Cart.xml" XSLT="Cartsheet.xslt" Keyword="Cart" />
      </TemplateMapper>
    </configuration>

When I pass in value of attribute Keyword as "product" I want LINQ to return me value of XML and XSLT attributes as Dictionary of string and string. 当我将属性关键字的值作为“产品”传递时,我希望LINQ将XML和XSLT属性的值作为字符串和字符串字典返回给我。

I have so far tried: 到目前为止,我已经尝试过:

               var Template="Product"
                var dictionary = (from el in xmlElement.Descendants("TemplateMapper") 
                              let xElement = el.Element("Template") 
                              where xElement != null && xElement.Attribute("Keyword").Value == Template 
                              select new
                                         {
                                             XML = el.Attribute("XML").Value, 
                                             XSLT= el.Attribute("XSLT").Value
                                         }).ToDictionary(pair => pair.XML, pair => pair.XSLT);

            KeyValuePair<string, string> templateValues = dictionary.FirstOrDefault();

It's giving be an error "Object reference not set to instance of an object". 出现错误“对象引用未设置为对象实例”。 Can anyone spot what wrong am I doing? 谁能发现我在做什么错? Helps really appreciated. 帮助真的很感激。

I would try following: 我会尝试以下操作:

var dictionary = (from t in xdoc.Root.Element("TemplateMapper").Elements("Template")
                  where (string)t.Attribute("Keyword") == Template
                  select new {
                      XML = (string)t.Attribute("XML"),
                      XSLT = (string)t.Attribute("XSLT")
                  }).ToDictionary(x => x.XML, x => x.XSLT);

(string)XAttribute does not throw an exception when attribute is not found, so it's better that XAttribute.Value . 当没有找到属性时, (string)XAttribute不会引发异常,因此最好使用XAttribute.Value

replace your code with this 用这个替换你的代码

           var Template="Product"
            var dictionary = (from el in xmlElement.Descendants("TemplateMapper") 
                          let xElement = el.Element("Template") 
                          where xElement != null && xElement.Attribute("Keyword").Value == Template 
                          select new
                                     {
                                         XML = xElement .Attribute("XML").Value, 
                                         XSLT= xElement .Attribute("XSLT").Value
                                     }).ToDictionary(pair => pair.XML, pair => pair.XSLT);

        KeyValuePair<string, string> templateValues = dictionary.FirstOrDefault();

the element you are at currently is xElement not el 您当前所在的元素是xElement not el

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