[英]jquery json not returning value
I am using jquery to submit a form using serialize and all is well except if I input more than 1 box. 我使用jquery使用序列化提交表单,一切都很好,除非我输入超过1个框。 If I input 1 box, the msg.box appears in #BA_addbox.
如果我输入1个框,则msg.box出现在#BA_addbox中。 If however I enter more than 1 box using , as delimiter, then no msg is shown and no json tab appears in firebug.
但是,如果我使用as作为分隔符输入多个框,则不显示消息,并且在firebug中不显示json选项卡。 just the html which is correct.
只是正确的HTML。 Where have I gone wrong with code.
代码在哪里出错了?
I have created an array and using foreach with explode to seperate the values but no multiple value being returned. 我创建了一个数组并使用foreach with explode来分隔值,但没有返回多个值。 Thanks
谢谢
UPDATE: vars are being collected in the php script like thus: 更新: vars正在PHP脚本中收集,如下所示:
php code PHP代码
$dept = mysql_real_escape_string($_POST['customerdept']);
$company = mysql_real_escape_string($_POST['BA_customer']);
$address = mysql_real_escape_string($_POST['customeraddress']);
$service = mysql_real_escape_string($_POST['BA_service']);
$box = mysql_real_escape_string($_POST['BA_box']);
$date = DateTime::createFromFormat('d/m/Y', $_POST['BA_destdate']);
$destdate = $date - > format('Y-m-d');
$authorised = mysql_real_escape_string($_POST['BA_authorised']);
$submit = mysql_real_escape_string($_POST['submit']);
$array = explode(",", $_POST['BA_box']);
if (isset($_POST['submit'])) {
foreach ($array as $box) {
//$sql = "INSERT INTO `act` (service, activity, company, address, department, user, destroydate, date, item, new) VALUES ('$service', '$activity', '$company', '$address', '$dept', '$authorised', '$destdate', NOW(), '$box', 1)";
//$result = runSQL($sql) or die(mysql_error());
$form=array('dept'=>$dept,
'company'=>$company,
'address'=>$address,
'service'=>$service,
'box'=>$box,
'destroydate'=>$destdate,
'authorised'=>$authorised,
'submit'=>$submit);
$result=json_encode($form);
echo $result;
}
}
jquery code jquery代码
submitHandler: function() {
if ($("#BA_boxform").valid() === true) {
var data = $("#BA_boxform").serialize();
$.post('/domain/admin/requests/boxes/boxesadd.php', data, function(msg) {
$("#BA_addbox").html("You have entered box(es): " + "<b>" + msg.box + "</b><br /> You may now close this window.");
$("#BA_boxform").get(0).reset();
}, 'json');
} else
{
return;
}
},
success: function(msg) {
//$("#BA_addbox").html("You have entered a box");
//$("#BA_boxform").get(0).reset();
}
First fix the php to return a valid json array. 首先修复php以返回有效的json数组。
if (isset($_POST['submit'])) {
foreach ($array as $box) {
//$sql = "INSERT INTO `act` (service, activity, company, address, department, user, destroydate, date, item, new) VALUES ('$service', '$activity', '$company', '$address', '$dept', '$authorised', '$destdate', NOW(), '$box', 1)";
//$result = runSQL($sql) or die(mysql_error());
$form=array('dept'=>$dept,
'company'=>$company,
'address'=>$address,
'service'=>$service,
'box'=>$box,
'destroydate'=>$destdate,
'authorised'=>$authorised,
'submit'=>$submit);
$result[]=$form;
}
echo json_encode( $result );
}
Then the msg parameter in the post callback should be an array of results, so you can't just do msg.box
to get the list of boxes. 然后post回调中的msg参数应该是结果数组,因此你不能只使用
msg.box
来获取框的列表。 I would suggest something like this: 我会建议这样的事情:
boxes = jQuery.map(msg,function(item){
return item.box;
}).join(',');
That extracts the box property from each item in the array and joins them into a comma separated list. 它从数组中的每个项目中提取box属性,并将它们连接到逗号分隔列表中。 You can then display that list like this:
然后,您可以像这样显示该列表:
$("#BA_addbox").html("You have entered box(es): " + "<b>" + boxes +
"</b><br /> You may now close this window.");
Given these changes, your code works for me. 鉴于这些变化,您的代码适合我。 If you're having other problems, I suggest you post more of your html - in particular your form structure.
如果您遇到其他问题,我建议您发布更多的html - 特别是您的表单结构。 It's possible your form isn't submitted the correct values to get a valid response from the server.
您的表单可能未提交正确的值以从服务器获得有效响应。
Per @nnnnnn: Per @nnnnnn:
Your resulting json looks like the structure below if there is more than one box. 如果有多个框,则生成的json看起来像下面的结构。 This is invalid json, and therefore can not be reliably parsed.
这是无效的json,因此无法可靠地解析。
{
...
}{
...
}
To fix this, you have to add the arrays to another array, then encode the parent array. 要解决此问题,您必须将数组添加到另一个数组,然后对父数组进行编码。
$box = mysql_real_escape_string($_POST['BA_box']);
$array = explode(",", $_POST['BA_box']);
$output = Array();
if (isset($_POST['submit'])) {
foreach ($array as $box) {
//$sql = "INSERT INTO `act` (service, activity, company, address, department, user, destroydate, date, item, new) VALUES ('$service', '$activity', '$company', '$address', '$dept', '$authorised', '$destdate', NOW(), '$box', 1)";
//$result = runSQL($sql) or die(mysql_error());
$form=array('dept'=>$dept,
'company'=>$company,
'address'=>$address,
'service'=>$service,
'box'=>$box,
'destroydate'=>$destdate,
'authorised'=>$authorised,
'submit'=>$submit);
//Add to a parent array instead
$output[] = $form;
}
//encode the entire array
$result = json_encode( $output );
echo $result;
}
This will result in the following structure and for a variable data
that contains the parsed json each box can be retrieved via data[0]
, data[1]
etc. 这将导致以下结构,对于包含已解析的json的可变
data
,可以通过data[0]
, data[1]
等检索每个框。
[
{
...
},
{
...
}
]
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