从Ajax调用C＃网络方法

Question

I need to make a call to a webmethod that is defined in this class

<%@ WebService Language="C#" Class="emt7anReyady.myService" %>

using System;
using System.Web;
using System.Web.Services;
using System.Web.Services.Protocols;
using System.Linq;
using System.Web.Security;

namespace emt7anReyady
{
    [WebService(Namespace = "http://tempuri.org/")]
    [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
    // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line. 
    [System.Web.Script.Services.ScriptService]
    public class myService : System.Web.Services.WebService
    {
        [WebMethod]
        [System.Web.Script.Services.ScriptMethod]
        public void test()
        {
            Context.Response.Redirect("http://www.google.com");
        }
    }
}

and I have make an Ajax call like this one

function getData() {
                 $.ajax({
                     type: "POST",
                     url: "myService.asmx/test",
                     data: "{}",
                     contentType: "application/json; charset=utf-8",
                     dataType: "json",
                     success: function () {
                         alert("succesed")
                     },
                     failure: function () {
                         alert("faild")
                     }
                 });
             }

the problem that the call is failed and in the chrome console I get this !!

Answer 1

You are getting ThreadAbort response due to using of Response.Redirect .

It is not exactly clear what you are trying to achieve with this code - if you want proxy some other site you need to read and forward response...

Answer 2

It is because of Response.Redirect you are using in your WebMethod. If you really want to redirect to some other page, do it from the success block.

.
.

success: function () {
                     window.open('http://www.google.com');
                 },
.
.

you can also make use of document.location instead of window.open