Java：从字符串中删除数值

Question

I have suceeded with the help of this community in removing numeric values from user input, however, my code below will only retrieve the alpha characters before the numeric that has been removed:

import java.util.Scanner;

public class Assignment2_A {

    public static void main(String[] args) {
        Scanner firstname = new Scanner(System.in);
        String firstname1 = firstname.next();
        firstname1 = firstname1.replaceAll("[^A-Z]","");
        System.out.println(firstname1);
    }
}

For example if user input = S1234am, I am only getting back: S. How do I retrieve the remaining characters in the string?

Answer 1

这将删除所有数字：

firstname1 = firstname1.replaceAll("\\d","");

Answer 2

You can use:

firstname1 = firstname1.replaceAll("[0-9]","");

This will remove all numeric values from String firstName1 .

    String firstname1 = "S1234am";
    firstname1 = firstname1.replaceAll("[0-9]","");
    System.out.println(firstname1);//Prints Sam

Answer 3

Your regular expression [^AZ] is currently only configured to preserve upper-case letters. You could try replacing it with [^A-Za-z] to keep the lower-case letters too.

Answer 4

How to remove numeric values from a string:

to do this it will be enough

str.replaceAll("[^A-Za-z]","");

but what if your string contain characters like:

String str = "stackoverflow elenasys +34668555555 # Пивоварова Пивоварова հայեր հայեր አማሪኮ     አማሪኮ kiểm tra kiểmtra ตรวจสอบ ตรวจสอบ التحقق من التحقق من";

most of the characters will be removed too, so this is a better option :

str = str.replaceAll("[\\d.]", "");

to remove all numeric values and get as result:

stackoverflow elenasys + # Пивоварова Пивоварова հայեր հայեր አማሪኮ     አማሪኮ kiểm tra kiểmtra ตรวจสอบ ตรวจสอบ التحقق من التحقق من

Answer 5

Your regex:

[^A-Z]

matches anything which is not an uppercase letter .

Which means any lowercase letter will match too.

You should probably use:

[^A-Za-z]

as a regex instead.

Note also that this will not account for anything other than ASCII. It may, or may not, be what you want.

Answer 6

public static void main(String[] args) {
    String address = "34732483dhshdsdhajsa8ejdsdd";
    char[] chars = address.toCharArray();
    String aString = "";

    for (int i = 0; i < chars.length; i++) {
        if (!Character.isDigit(chars[i])) {
            aString =aString + chars[i]; 


        }

    }System.out.println(aString);



}

Answer 7

/*Remove numbers from given specific string*/
public class NewClass6 {

    public static void main(String[] args){
        String s= "hello647hi74joke";
        char[] ch= s.toCharArray();
        System.out.println("Result = " + getString(ch));
    }

    static String getString(char[] ch){
        int m = 0;
        char[] chr = new char[50];
        char[] k = {'0','1','2','3','4','5','6','7','8','9'};

        for(int i = 0; i < ch.length; i++){
           for(int j = 0; j < k.length; j++){  
               if(ch[i]==k[j]){
                   m--;
                   break;
               }
               else {
                   chr[m]=ch[i];
               }
            }
            m++;
         }

         String st = String.valueOf(chr);
         return st;
     }
}