当我尝试打印字符串时，为什么我的程序打印“ .project”？

Question

I'm supposed to make a program that inputs three arguments which will later be calculated. The first and third arguments are numbers in string format (ex. "three") while the second argument is the operation (ex. "-" "+"). Everything works fine except when I use the "*" operation. I tried to print the string as it passes the parser function because that's where the error occurs and it prints ".project" instead of the number in string format.

static int converter(String x)
{
    System.out.println(x); 
    int value = 0;
    String zero = "0";
    String one = "1";
    String two = "2";
    String three = "3";
    String four = "4";
    String five = "5";
    String six = "6";
    String seven = "7";
    String eight = "8";
    String nine = "9";
    String ten = "10";
    String eleven = "11";
    String twelve = "12";
    String thirteen = "13";
    String fourteen = "14";
    String fifteen = "15";
    String sixteen = "16";
    String seventeen = "17";
    String eighteen = "18";
    String nineteen = "19";
    String twenty = "20";
    String thirty = "30";
    String forty = "40";
    String fifty = "50";
    String sixty = "60";
    String seventy = "70";
    String eighty = "80";
    String ninety = "90";
    if(x.compareTo("zero")==0)
        value = Integer.parseInt(zero);
    else if(x.compareTo("one")==0)
        value = Integer.parseInt(one);
    else if(x.compareTo("two")==0)
        value = Integer.parseInt(two);
    else if(x.compareTo("three")==0)
        value = Integer.parseInt(three);
    else if(x.compareTo("four")==0)
        value = Integer.parseInt(four);
    else if(x.compareTo("five")==0)
        value = Integer.parseInt(five);
    else if(x.compareTo("six")==0)
        value = Integer.parseInt(six);
    else if(x.compareTo("seven")==0)
        value = Integer.parseInt(seven);
    else if(x.compareTo("eight")==0)
        value = Integer.parseInt(eight);
    else if(x.compareTo("nine")==0)
        value = Integer.parseInt(nine);
    else if(x.compareTo("ten")==0)
        value = Integer.parseInt(ten);
    else if(x.compareTo("eleven")==0)
        value = Integer.parseInt(eleven);
    else if(x.compareTo("twelve")==0)
        value = Integer.parseInt(twelve);
    else if(x.compareTo("thirteen")==0)
        value = Integer.parseInt(thirteen);
    else if(x.compareTo("fourteen")==0)
        value = Integer.parseInt(fourteen);
    else if(x.compareTo("fifteen")==0)
        value = Integer.parseInt(fifteen);
    else if(x.compareTo("sixteen")==0)
        value = Integer.parseInt(sixteen);
    else if(x.compareTo("seventeen")==0)
        value = Integer.parseInt(seventeen);
    else if(x.compareTo("eighteen")==0)
        value = Integer.parseInt(eighteen);
    else if(x.compareTo("nineteen")==0)
        value = Integer.parseInt(nineteen);
    else if(x.compareTo("twenty")==0)
        value = Integer.parseInt(twenty);
    else if(x.compareTo("thirty")==0)
        value = Integer.parseInt(thirty);
    else if(x.compareTo("forty")==0)
        value = Integer.parseInt(forty);
    else if(x.compareTo("fifty")==0)
        value = Integer.parseInt(fifty);
    else if(x.compareTo("sixty")==0)
        value = Integer.parseInt(sixty);
    else if(x.compareTo("seventy")==0)
        value = Integer.parseInt(seventy);
    else if(x.compareTo("eighty")==0)
        value = Integer.parseInt(eighty);
    else if(x.compareTo("ninety")==0)
        value = Integer.parseInt(ninety);
    else { 
        System.out.println("Error.");
        System.exit(0);
    }
    return value;
}

The program runs okay if I enter " * " instead of "*".

Answer 1

Because when you call your program, the shell expands the wildcard.

Consider the similary between

dir *.txt

and

java MyProg.class 2 * 3

The asterisk will be replaced by all the files in the directory.