[英]Ajax Upload with JQuery and PHP
I have a problem with Ajax uploading using Jquery and PHP.. Although there're many stackoverflow posts discussing the same subject, I didn't find one that matches my case. 我有使用Jquery和PHP上传Ajax的问题。虽然有很多stackoverflow帖子讨论相同的主题,但我找不到一个与我的情况相符的帖子。
HTML : HTML:
<form action="uploadrecord.php" id="upload_record_form" method="post" enctype="multipart/form-data">
<div id="upload_record_form_result"></div>
<ul>
<li><input type="file" name="uploadrecord" id="uploadrecord"/></li>
</ul>
<progress></progress>
</form>
</div>
Javascript : Javascript:
$('#uploadrecord').live('change', function(event) {
var formData = new FormData($('#upload_record_form')[0]);
$.ajax({
url: $('#upload_record_form').attr('action'),
type: 'POST',
enctype: 'multipart/form-data',
xhr: function() {
myXhr = $.ajaxSettings.xhr();
if (myXhr.upload) {
myXhr.upload.addEventListener('progress', progressHandlingFunction, false);
}
return myXhr;
},
success: completeHandler = function(data) {
$('#upload_record_form_result').html(data);
},
error: errorHandler = function() {
alert("Failure");
},
data: formData,
cache: false,
contentType: false,
processData: false
}, 'json');
});
PHP PHP
<?php
if (isset($_FILES['uploadrecord'])) {
if ((!empty($_FILES["uploadrecord"])) && ($_FILES['uploadrecord']['error'] == 0)) {
$filename = basename($_FILES['uploadrecord']['name']);
$ext = substr($filename, strrpos($filename, '.') + 1);
$types = array(
'video/mp4', 'video/3gpp', 'video/divx', 'video/flv', 'video/mpeg', 'video/mpeg-2', 'video/mpeg4', 'video/mpeg4'
);
$type = $_FILES['uploadrecord']['type'];
if (in_array($type, $types) && $_FILES["uploadrecord"]["size"] < 20000000) {
$new = sha1(date('Y/m/d H:i:s'));
$newname = dirname(__FILE__) . '/records/' . $new . '.' . $ext;
if ((move_uploaded_file($_FILES['uploadrecord']['tmp_name'], $newname))) {
echo 'done';
} else {
echo 'failed 1';
}
}
} else {
echo 'failed 2';
}
} else {
echo 'Upload failed 3';
}
When I try the previous code, and upload a record file, it displays "failed 2", meaning that the "error" code is different from 0. 当我尝试上一个代码并上传一个记录文件时,它会显示“failed 2”,这意味着“error”代码与0不同。
when I var_dump the array $_FILES['uploadrecord']...this is what I get: 当我var_dump数组$ _FILES ['uploadrecord']时...这就是我得到的:
array (size=5)
'name' => string 'Nao Robot.flv' (length=13)
'type' => string '' (length=0)
'tmp_name' => string '' (length=0)
'error' => int 1
'size' => int 0
I can't figure out, why 'tmp_name' and type are set to empty strings, and why the size is set to 0. 我无法弄清楚,为什么'tmp_name'和type被设置为空字符串,以及为什么将size设置为0。
Where's the problem exactly? 究竟问题出在哪里? is it from the client or server side scripting?
是来自客户端还是服务器端的脚本?
Thanks in advance 提前致谢
ON MAC OSX: 在MAC OSX上:
1) Go to /etc/php.ini 1)转到/etc/php.ini
2) Open the file with permission to write/read 2)打开具有写入/读取 权限的文件
3) Search for line: 3)搜索行:
upload_max_filesize = 2M
4)Change to, for example, 6MB ou more: 4)例如,更改为6MB以上:
upload_max_filesize = 6M
5) Save and restart apache with command: 5)使用命令保存并重启apache:
sudo apachectl restart
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