包括两个日期之间的差额

Question

The following code gives me the correct answer

//$start_date = '1/1/2013'
//$end_date = '1/7/2013'
$diff_num = strtotime($end_date) - strtotime($start_date) + 1; 
$diff_days = ceil($diff_num + 86400) / 86400;

However, it seems to me that there has got to be a better answer than this. I don't like having to add a day to be completely inclusive of the range. I want to include all the days in the range not the space in between. Thanks for any help.

Answer 1

You could use the DateTime object like so :

$datetime1 = new DateTime('2013-1-1');
$datetime2 = new DateTime('2013-7-1');
$interval = $datetime1->diff($datetime2);
$interval->add(new DateInterval('P1D')); // adds one day

But yes, you definitly have to add one day "by hand".