通过创建未抛出的“新Exception（）”来在测试时隐藏JUnit的堆栈跟踪？

Question

I am testing one of my methods w/ JUnit and the method takes an Exception as a parameter. The test looks roughly like this:

public void testSomething() {
...
  callMethod(param1, new Exception("ignore exception"));
}

When I do this, the act of creating an Exception (not throwing it) dumps this to System.err

java.lang.Exception: ignore exception at ...testSomething at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at junit.framework.TestCase.runTest(TestCase.java:176) at junit.framework.TestCase.runBare(TestCase.java:141

Is there any way to suppress this output? I Goggled for everything I could think of, but it picks up all sorts of unrelated stuff.

Answer 1

仅供参考，函数调用在其中做了一个ex.printStackTrace（）调试语句，我忘了取出它，所以亚当是正确的。

Answer 2

您可以在不调用父构造函数的情况下从Exception派生类吗？