Java正则表达式通过使用不同的分隔符来分割字符串

Question

Suppose I want to split a string by either space character or the %20 string, how should I write my regex?

I tried the following, but it didn't work.

String regex = "[\\s+, %20]";
String str1 =  "abc%20xyz";
String str2 = "abc xyz";

str1.split(regex);
str2.split(regex);

The regex doesn't seem to work on str1 .

Answer 1

use the alternation | :

String regex = "(?:\\s+|%20)+";

Answer 2

String regex = "(\\s{1}+|%20{1}+)";

Answer 3

If you want to split by ONE space or ONE "%20", try this:

String regex = "(\\s|%20)";

If you want to split by AT LEAST ONE space or AT LEAST ONE "%20", then try this:

String regex = "(\\s+|(%20)+)";