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为什么随机不起作用?

[英]Why doesn't random work?

I have to write a method, which is able to find random Vacation in the database. 我必须编写一个方法,该方法能够在数据库中找到随机的Vacation。 But when I use this part in the test 但是当我在测试中使用这部分时

Random id = new Random();
vacationId = id.nextInt(2500);

I get NullPoiterExeption . 我得到NullPoiterExeption But when i just print 但是当我打印时

vacationId = 2500;

or some other number, everything is okay. 或其他一些数字,一切正常。

This is the whole method 这就是整个方法

public Vacation findRandomVacation() {
    Integer vacationId = null;
    Query query = entityManager.createQuery("from Vacation v where v.id = :id")
                .setParameter("id", vacationId);
    if  ( query.getResultList().isEmpty()) {
        Random id = new Random();
        vacationId = id.nextInt(2500);
        query = entityManager.createQuery("from Vacation v where v.id = :id")
               .setParameter("id", vacationId);
    }
    return (Vacation) query.getResultList().get(0);
}

And this is the main body of the test: 这是测试的主体:

@Test
public void testVacationApprovalResultDao () {
    Vacation testVacation = findRandomVacation();
    VacationApproval testVacationApproval = findVacationApprovalDAO(testVacation);
    List<VacationApprovalResult> testVacationApprovalResult = getVacationApprovalResultByManager(testVacationApproval);
    Set<VacationApprovalResult> setVacationApprovalResult = testVacationApproval.getVacationApprovalResults();   //mistake is here
    List<VacationApprovalResult> testVacationApprovalResult2 = new ArrayList<VacationApprovalResult> ();
    testVacationApprovalResult2.addAll(setVacationApprovalResult);

    assertEquals(testVacationApprovalResult, testVacationApprovalResult2);
}

I suspect this is where you get the NullPointerException : 我怀疑是您获取NullPointerException

Integer vacationId = null;
Query query = entityManager.createQuery("from Vacation v where v.id = :id")
            .setParameter("id", vacationId);

This is before you've set it from Random - you're setting the parameter to a null value. 这是您从Random设置之前 -将参数设置为null值。

To be honest though, this isn't a good way of finding a random record from the database unless you know that there are vacations with every ID from 0 to 2499. 不过,老实说,这不是从数据库中查找随机记录的好方法,除非您知道每个ID从0到2499的假期。

Basically you want the random choice to be performed at the database as that's where the data is. 基本上,您希望在数据库上执行随机选择,因为这就是数据所在的位置。 An alternative would be to fetch all the vacation IDs, pick a random element of that set, and then load the data for it - but that's not pleasant either. 一种替代方法是获取所有休假ID,从该集合中选择一个随机元素,然后为其加载数据-但这也不令人满意。

change 更改

 Integer vacationId = null;

to

Integer vacationId = 0;

Why would you do this ? 你为什么要这样做 ?

Integer vacationId = null;
Query query = entityManager.createQuery("from Vacation v where v.id = :id")
            .setParameter("id", vacationId);

Is it possible for vacationId to hold a null value ? VacationId是否可以保留null值? if not then try with the random at once. 如果没有,则立即尝试随机。

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