[英]Populate dropdown based on row values one time
Hey guys I have a table that I built, but I am trying to add some stuff into it. 大家好,我有一张桌子,但我想在桌子上加些东西。 I want to have a dropdown gets populated based on the dates that are in the database.
我想根据数据库中的日期填充下拉列表。
This is how my db looks: 这是我的数据库的外观:
http:// i.imgur.com/YKgjf4C.png http:// i.imgur.com/YKgjf4C.png
I want it to show the dates from pat_date a single time and only the ones that are in the database, skipping the ones that aren't there, and limiting the so called duplicates it to 1 date per line, bascially not listing like 07/11/2013 about 14 times. 我希望它一次显示来自pat_date的日期,并且仅显示数据库中的日期,跳过那些不存在的日期,并将所谓的重复项限制为每行1个日期,基本上不会像07 / 11/2013约14次。
_________________
| SELECT DATE |v|
-----------------
| 07/02/2013 | |
| 07/08/2013 | |
| 07/11/2013 | |
--------------| |
How am I able to do this with my current script? 如何使用当前脚本执行此操作?
Right now I have it like this 现在我有这样
http:// i.imgur.com/r0zCrDj.png http:// i.imgur.com/r0zCrDj.png
but its annoying going through every date, and instead would be easier if i could already have the dates with a dropbox i know has some people scheduled on it. 但是它烦人的经历了每个日期,如果我已经有了一个带有保管箱的日期,而我知道有人安排了它,那么它将变得更容易。
How is this possible? 这怎么可能?
you can use a distinct query 您可以使用不同的查询
SELECT distinct `date` from `yourtable`;
I would also suggest you storing your dates as a date field, this will make sorting and manipulating based on those values much easier. 我还建议您将日期存储为日期字段,这将使基于这些值的排序和操作更加容易。
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