[英]how to add two ListViews in parallel?
Hi, I am newbie to Android. 嗨,我是Android的新手。 Is it possible to add two ListView
parallel on the same screen? 是否可以在同一屏幕上添加两个ListView
并行? I already use one ListView
and displaying item using ListAdapter
, but actually I need it to this: When it displays the item and scroll horizontal, I want the first TextView
to freeze, and when I scroll vertical, it will scroll. 我已经使用一个ListView
并使用ListAdapter
显示项目,但实际上我需要它:当它显示项目并滚动水平时,我希望第一个TextView
冻结,当我滚动垂直时,它将滚动。
xml file: xml文件:
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="#ffffff"
android:orientation="horizontal">
<!-- Main ListView
Always give id value as list(@android:id/list)
-->
<HorizontalScrollView
android:layout_width="wrap_content"
android:layout_height="fill_parent"
android:id="@+id/horizontalScrollView">
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:background="#ffffff"
android:orientation="vertical">
<TableRow
android:id="@+id/tableRow1"
android:scrollbarAlwaysDrawHorizontalTrack="true"
android:layout_height="wrap_content"
android:layout_width="match_parent">
<TextView
android:id="@+id/TextView2"
android:text="GRPName"
android:background="#A513FF"
android:textColor="#000000"
android:layout_width="150dp"
android:padding="3dip"
/>
<TextView
android:id="@+id/TextView3" android:text="QTY"
android:background="#A513FF"
android:textColor="#000000"
android:layout_width="60dp"
android:gravity="right"
android:padding="3dip" />
<TextView
android:id="@+id/TextView4" android:text="BUD"
android:background="#A513FF"
android:textColor="#000000"
android:layout_width="60dp"
android:gravity="right"
android:padding="3dip" />
<TextView
android:id="@+id/TextView5" android:text="STK"
android:background="#A513FF"
android:textColor="#000000"
android:layout_width="60dp"
android:gravity="right"
android:padding="3dip" />
<TextView
android:id="@+id/TextView2" android:text="DIF"
android:background="#A513FF"
android:gravity="right"
android:textColor="#000000"
android:layout_width="60dp"
android:padding="3dip"
/>
<TextView
android:id="@+id/TextView3" android:text="DIF%"
android:background="#A513FF"
android:textColor="#000000"
android:layout_width="60dp"
android:gravity="right"
android:padding="3dip" />
</TableRow>
<ListView
android:id="@android:id/list"
android:smoothScrollbar="true"
android:layout_width="fill_parent"
android:layout_weight="1"
android:layout_height="fill_parent"/>
</LinearLayout>
</HorizontalScrollView>
ListAdapter: ListAdapter:
ListAdapter adapter = new SimpleAdapter(this, contactList,
R.layout.list_item,
new String[] { TAG_GRPNAME, TAG_QNT, TAG_BUDGET, TAG_STOCK, TAG_DIFF, TAG_DIFF_P, },
new int[] {
R.id.l2, R.id.l3, R.id.l4, R.id.l5, R.id.l6, R.id.l7});
setListAdapter(adapter);
ListView lv = getListView();
}
I want to freeze TAG_GRPNAME
and R.id.l2
. 我想冻结TAG_GRPNAME
和R.id.l2
。
Try something like this: 尝试这样的事情:
main.xml main.xml中
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
<LinearLayout android:layout_weight="1"
android:layout_height="fill_parent"
android:layout_width="fill_parent">
<ListView android:id="@+id/listview1"
android:layout_height="fill_parent"
android:layout_width="fill_parent">
</ListView>
</LinearLayout>
<LinearLayout android:layout_weight="1"
android:layout_height="fill_parent"
android:layout_width="fill_parent">
<ListView android:id="@+id/listview2"
android:layout_height="fill_parent"
android:layout_width="fill_parent">
</ListView>
</LinearLayout>
</LinearLayout>
Where 2 LinearLayout
's will have weight 1. 其中2个LinearLayout
的权重为 1。
And from code behind : 从代码背后 :
ListView ls1,ls2;
String colors[] = {"Red","Blue","White","Yellow","Black", "Green","Purple","Orange","Grey"};
private String phones[] = {"Android", "Blackberry", "iPhone","Windows Phone"};
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
ls1 = (ListView) findViewById (R.id.listview1);
ls2 = (ListView) findViewById (R.id.listview2);
ls1.setAdapter(new ArrayAdapter<String> (this, android.R.layout.simple_list_item_1, colors));
ls2.setAdapter(new ArrayAdapter<String> (this, android.R.layout.simple_list_item_1, phones));
}
a little change on @ridoy's code is here and may your work done...! @ ridoy代码的一点变化就在这里,可能你的工作已经完成......!
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent" >
<ListView
android:id="@+id/list1"
android:layout_width="0dp"
android:layout_height="fill_parent"
android:layout_weight=".50" >
</ListView>
<ListView
android:id="@+id/list2"
android:layout_width="0dp"
android:layout_height="fill_parent"
android:layout_weight=".50" >
</ListView>
</LinearLayout>
still is there any query, plz ask. 仍然有任何疑问,请问。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.