jQuery的.done（）和.always（）永远不会被调用

Question

I'm trying to do a simple ajax api call, but my jQuery .done() and .always() callbacks are never getting run, even after a successful call.

Here's where I do the api call:

join: (e) ->

    e.preventDefault()
    email = $('.email').val()

    $.ajax(
      type: 'POST'
      url: '/api/email'
      data: { email: email }
    ).done((msg) ->
      console.log 'POST success'
      console.log msg
    ).always((msg) ->
      console.log 'Always'
    )

Here's the post from my controller:

app.post '/api/email', (req, res) ->

    console.log req.body

The problems that my server is correctly receiving the data from the api call, but my jQuery callbacks never get fired.

{ email: 'test@email.com' } // What gets logged server-side

EDIT

So I tried adding a .fail() method and switched up the code a bit to see if my syntax was wrong, but this new code is still functioning like the old code.

request = $.ajax(
  type: 'POST'
  url: '/api/email/beta'
  data: { email: email }
)

request.done( (msg) ->
  console.log 'POST success'
  console.log msg
)

request.fail( (msg) ->
  console.log 'POST Fail'
  console.log msg
)

request.always( () ->
  console.log 'Always'
)

EDIT 2

I just realized that the POST is actually "failing", but after 4.1 mins... But the weird thing is that I'm still getting the data in the req.body object...?

Here's a screenshot of network from chrome tools:

Answer 1

Looks like you receive the request at the server (and log it), but then don't do anything about it. This eventually leads to a timeout. Change it to

app.post '/api/email', (req, res) ->
    console.log req.body
    res.write(JSON.stringify({success:true})/* or whatever*/);
    res.end();

Maybe you're using some framework with special methods on the res object; if so then look up its documentation about how to answer a request.

Answer 2

Try like this:

$.ajax({
      type: 'POST'
      url: '/api/email'
      data: { email: email}
    }).done((msg) ->
      console.log 'POST success'
      console.log msg
    ).always((msg) ->
      console.log 'Always'
    )