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如何在python中组合两个numpy数组元素?

[英]How do I combine two numpy arrays element wise in python?

I have two numpy arrays: 我有两个numpy数组:

A = np.array([1, 3, 5, 7])
B = np.array([2, 4, 6, 8])

and I want to get the following from combining the two: 我想从两者结合得到以下内容:

C = [1, 2, 3, 4, 5, 6, 7, 8]

I'm able to get something close by using zip , but not quite what I'm looking for: 我可以通过使用zip获得一些东西,但不是我正在寻找的东西:

>>> zip(A, B)
[(1, 2), (3, 4), (5, 6), (7, 8)]

How do I combine the two numpy arrays element wise? 我如何组合两个numpy数组元素?


I did a quick test of 50,000 elements in each array (100,000 combined elements). 我对每个阵列中的50,000个元素进行了快速测试(100,000个组合元素)。 Here are the results: 结果如下:

User Ma3x:      Time of execution: 0.0343832323429      Valid Array?:  True
User mishik:    Time of execution: 0.0439064509613      Valid Array?:  True
User Jaime:     Time of execution: 0.02767023558        Valid Array?:  True

Tested using Python 2.7, Windows 7 Enterprise 64-bit, Intel Core i7 2720QM @2.2 Ghz Sandy Bridge, 8 GB Mem 使用Python 2.7,Windows 7企业版64位,英特尔酷睿i7 2720QM @ 2.2 Ghz Sandy Bridge,8 GB Mem进行测试

Use np.insert : 使用np.insert

>>> A = np.array([1, 3, 5, 7])
>>> B = np.array([2, 4, 6, 8])
>>> np.insert(B, np.arange(len(A)), A)
array([1, 2, 3, 4, 5, 6, 7, 8])

You can also use slices : 你也可以使用切片:

C = np.empty((A.shape[0]*2), dtype=A.dtype)
C[0::2] = A
C[1::2] = B
>>> import numpy as np
>>> A=np.array([1,3,5,7])
>>> B=np.array([2,4,6,8])
>>> C=np.dstack([A,B])
>>> D=C.reshape((1,8))[0]
>>> D
array([1, 2, 3, 4, 5, 6, 7, 8])

Some answers suggested sorting, but since you want to combine them element-wise sorting won't achieve the same result. 一些答案建议排序,但由于你想要将它们组合在一起,因此元素排序将无法实现相同的结果。

Here is one way to do it 这是一种方法

C = []
for elem in zip(A, B):
    C.extend(elem)

You can try this: 你可以试试这个:

C = sorted(A.tolist() + B.tolist())
  1. A.tolist() will yield [1, 3, 5, 7] A.tolist()将产生[1, 3, 5, 7]
  2. B.tolist() will yield [2, 4, 6, 8] B.tolist()会产生[2, 4, 6, 8]
  3. A.tolist() + B.tolist() - [1, 3, 5, 7, 2, 4, 6, 8] A.tolist() + B.tolist() - [1, 3, 5, 7, 2, 4, 6, 8] A.tolist() + B.tolist() [1, 3, 5, 7, 2, 4, 6, 8]
  4. sorted(...) - [1, 2, 3, 4, 5, 6, 7, 8] sorted(...) - [1, 2, 3, 4, 5, 6, 7, 8]

Without sorting: 没有排序:

C = [y for x in zip(A, B) for y in x]

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