定位变量，然后使用CSS选择器

Question

I have a variable $obj which has $(".major_data .commitment_box .commitment") as its value. No I want to use some CSS Selectors on $obj . How can I use them?

Selectors I want to use: :not(:last-child) .

My Code:

HTML:

<div class="major_data">
    <div class="commitment_box">
        <div class="commitment">
            <p>Alex:</p>
            <p>He's works great.</p>
        </div>
        <div class="commitment">
            <p>Alex 1:</p>
            <p>He's works great.</p>
        </div>
        <div class="commitment">
            <p>Alex 2:</p>
            <p>He's works great.</p>
        </div>
        <div class="commitment">
            <p>Alex 3:</p>
            <p>He's works great.</p>
        </div>
        <div class="commitment">
            <p>Alex 4:</p>
            <p>He's works great.</p>
        </div>
    </div>
</div>

CSS:

.major_data .commitment_box {
    text-align: center;
    height: 40px;
    overflow: hidden;
}
.major_data .commitment_box .commitment p {
    display: inline-block;
}
.major_data .commitment_box .commitment p:first-child {
    font-weight: bold;
    margin-right: 20px;
}

JS:

function tick() {
    var $obj = $(".major_data .commitment_box .commitment");
    $obj.first().delay(1000).fadeOut(function () {
        $obj.first().insertAfter($obj.last());
        tick();
    });
}
tick();

Result:
Demonstration

My Question:
I want to target the :not(:last-child) of the $obj . I know I can do that by simply writing that whole big value of $obj but is that possible only using the variable $obj ?

Thanks in advance.

Answer 1

$obj.find(':not(:last-child)')应该可以工作

Answer 2

$obj.not(':last') should be your target.

But I don't understand your if statement.