是否可以在具有相同PID的Shell脚本中运行多个可执行文件？

Question

I have a simple Shell script in which multiple executables will run sequentially. Every time a new executable starts to run, a new process with a new PID will start. Is it possible to run them with the same PID? I know for a shell script, we can use "source". But I do not know how to handle executables.

Answer 1

The PID is assigned by OS when shell creates a new process. There is no way to tell the OS to use some specific PID. So it's not possible.

Answer 2

In principle, I believe it should be possible, but in practice it would be very complicated and brittle.

The exec family of system calls in Linux allows a process to replace itself with an entirely new process, which holds on to the same PID. The tricky part would be to somehow "return" from the second process back to the first. When exec is called, the OS loads everything it needs to start running the new process, and wipes out every piece of state related to the current process (the one being replaced). And when the new process terminates, the OS releases all resources (including the PID) associated with that process.

So if you really wanted to do this, you would have to hijack how processes terminate in order to restart your original process rather than let the OS clean everything up. How can you do this? Well, execle and execvpe functions allow a program to specify the environment of the new process before starting the process. Since every process depends on libc (or equivalent) to bring up/tear down a process, you should be able to provide a custom libc which would re-start execution of your script, or exec another process. The great difficulty would be hacking such a libc . Additionally, you would have to figure out a good way for your master program to keep state even though the OS wipes away any memory it might have been using when it called exec . You can probably accomplish this with temporary files.

So long story short, don't do it. While it's kind of fun for me to sit here and think about the massive hacks that would be required to pull this off, it would be a huge pain and I'm sure there is a much more elegant solution to whatever problem you are actually trying to solve.