[英]Passing * as a command line argument
I wrote a C program to evaluate reverse polish notation by passing the expression as a command line argument, but when I pass * (for multiplication) then it is passing all the file names in that folder. 我编写了一个C程序,通过将表达式作为命令行参数传递来评估反向修饰符号,但是当我传递*(用于乘法)时,它将传递该文件夹中的所有文件名。
For example I passed this : 例如我通过了:
./rpn 10 20 30 + * ./rpn 10 20 30 + *
and when I print all the arguments result is, 当我打印所有参数时,
10
20
30
+
gcd
gcd.c
gcd.c~
rpn
rpn.c
rpn.c~
swapmacro
swapmacro.c argc :12
This is not a C problem. 这不是C问题。 You're using Bash (or some equivalent shell), where
*
is automatically expanded (before it gets anywhere near your program). 您正在使用Bash(或某些等效的Shell),其中
*
会自动展开*
(在到达程序附近的任何位置之前)。 You'll need to do something like this: 您需要执行以下操作:
./rpn 10 20 30 + "*"
You need to escape the *
eg by quoting it like "*"
or by escaping it like \\*
您需要对
*
进行转义,例如通过像"*"
一样将其引号或通过像\\*
那样转义它
The expansion of *
is done by the shell (before starting your program). *
的扩展由外壳程序完成(在启动程序之前)。 Read eg the Advanced Bash Scripting guide . 阅读例如《 高级Bash脚本指南》 。
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