[英]echo get syntax in quote
I have a script that send user to another url everytime he click (first click - first url, secound cluck - secound url etc.) 我有一个脚本,每次用户单击时,该脚本都会将用户发送到另一个URL(第一次单击-第一个URL,第二个敲响-第二个url等)
Here is the script: 这是脚本:
<?php
function urlredirect()
{
$value=0;
$url =array(
'http://www.link1.com/',
'http://www.link2.com/',
'http://www.link3.com/',
'http://www.link4.com/',
'http://www.link5.com/',
);
$urlc = count($url)-1;
if ($_COOKIE["cooki_name"]=='')
{
setcookie("cooki_name", $value,time()+86400);
header ("Location: $url[$value]");
}
if ($_COOKIE["cooki_name"]!='')
{
$getcookie=htmlspecialchars($_COOKIE["cooki_name"]);
if($urlc >$getcookie)
{
$getcookie=$getcookie+1;
}
setcookie("cooki_name", $getcookie,time()+86400);
header ("Location: $url[$getcookie]");
}
}
urlredirect();
?>
Now I need to add some echo and I do not know the right syntax. 现在,我需要添加一些回显,并且我不知道正确的语法。 Echo from get: 从得到的回声:
script.php?code=something script.php?code =某物
<?php
function urlredirect()
{
$value=0;
$url =array(
'http://www.link1.com/HERE-IS-THE-PLACE-WHERE-I-NEED-TO-ADD-code',
'http://www.link2.com/',
'http://www.link3.com/',
....
I was trying to add it by echo $_GET["code"]; 我试图通过echo $ _GET [“ code”];添加它。 but I fail. 但我失败了
construct your array like this to paas the url parameter in url 像这样构造数组以暂停url中的url参数
$url =array(
'http://www.link1.com/?code=some_value',
'http://www.link2.com/?code=some_value',
'http://www.link3.com/?code=some_value',
'http://www.link4.com/?code=some_value',
'http://www.link5.com/?code=some_value',
);
Now on your redirected page you can use 现在,您可以在重定向页面上使用
echo $_GET['code'];
Edit Based on comments 根据评论编辑
$url =array(
'http://www.link1.com/'.$_GET['code'],
'http://www.link2.com/'.$_GET['code'],
'http://www.link3.com/'.$_GET['code'],
'http://www.link4.com/'.$_GET['code'],
'http://www.link5.com/'.$_GET['code'],
);
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