[英]PHP dynamic page not working
I have a page that takes an SKU from a database and creates a page. 我有一个从数据库中获取SKU并创建页面的页面。 Example URL: http://example.com/index.php?sku=1234567
示例网址: http : //example.com/index.php?sku = 1234567
When I load a URL like this, it shows nothing - not even the table which I output with echo
. 当我加载这样的URL时,它什么也没有显示 - 甚至不是我用
echo
输出的表。 Below is my code: 以下是我的代码:
$sku = $_GET['sku'];
$result = mysqli_query($conn, "SELECT productname, price, producturl, productimg, productdesc, sku FROM table WHERE sku=" . $sku);
while ($row = mysqli_fetch_array($result)) {
echo '<h3>test</h3>';
echo '<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td><h4>'.$row["sku"].'</h4></td>
<td><h3>'.$row["productname"].'</h3></td>
<td rowspan="2"><img src="'.$row["productimg"].'" width="100%" alt="productimg"/></td>
</tr>
<tr>
<td colspan="2" rowspan="2"><p>'.$row["productdesc"].'</p></td>
</tr>
<tr>
<td><a class="button" href="'.$row["producturl"].'">View Product</a> <a class="alert button" href="">No Match</a> <a class="alert button" href="">Match</a></td>
</tr>
</table>';
}
I have connected to my database and have the <?php
and ?>
tags in there. 我已连接到我的数据库,并在那里有
<?php
和?>
标签。 I have noticed while playing around with it that if I remove this line: 我在玩它时注意到,如果我删除这一行:
while ($row = mysqli_fetch_array($result)) {
and also remove the closing }
, it works but does not display any data - just the table. 并删除关闭
}
,它可以工作,但不显示任何数据 - 只是表格。 I am not sure what is going on here. 我不确定这里发生了什么。
Simple. 简单。 your
mysqli_query
call returns no records. 你的
mysqli_query
调用没有返回任何记录。 Either no records are found, or there is an error. 没有找到记录,或者有错误。 Make your code a little more robust.
使您的代码更健壮。
$sku = $_GET['sku'];
if ($result = mysqli_query($conn, ...)) {
if (mysqli_num_rows($result) == 0) {
echo "no skus found";
} else {
while ($row = mysqli_fetch_array($result)) {
echo '<h3>test</h3>';
...
}
}
} else {
echo "something went wrong: ".mysqli_error();
}
(As a side note, please use parametrised queries, you are opening yourself up to SQL injection now. MySQLi is no magic bullet against this, you still have to validate / sanitize input.) (作为旁注,请使用参数化查询,您现在可以自己打开SQL注入.MySQLi对此没有魔力,您仍需要验证/清理输入。)
Display mysqli error on fault: 显示故障时的mysqli错误:
if (!mysqli_query($link, $sql)) {
printf("Errormessage: %s\n", mysqli_error($link));
}
Put $sku inside quotes. 把$ sku放在引号内。
<?php
$sku = $_GET['sku'];
$result = mysqli_query($conn, "SELECT productname, price, producturl, productimg, productdesc, sku FROM table WHERE sku = $sku");
while ($row = mysqli_fetch_array($result)) {
echo '<h3>test</h3>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td><h4>'.$row["sku"].'</h4></td>
<td><h3>'.$row["productname"].'</h3></td>
<td rowspan="2"><img src="'.$row["productimg"].'" width="100%" alt="productimg"/></td>
</tr>
<tr>
<td colspan="2" rowspan="2"><p>'.$row["productdesc"].'</p></td>
</tr>
<tr>
<td><a class="button" href="'.$row["producturl"].'">View Product</a> <a class="alert button" href="">No Match</a> <a class="alert button" href="">Match</a></td>
</tr>
</table>';
}
?>
I have managed to solve the issues that i have been having i had to remove the i from mysqli, but i have used the same piece of code on another site so it may be something to do with the server or database maybe. 我已经设法解决了我不得不从mysqli中删除i的问题,但我在另一个站点上使用了相同的代码,因此可能与服务器或数据库有关。 here is the code though'
这是代码虽然'
<?php
$sku = $_GET['sku'];
$objConnect = mysql_connect("host address","username","password") or die(mysql_error() . 'this is true death...');
$objDB = mysql_select_db("database");
$result = 'SELECT sku, productname, price, producturl, productimg, productdesc FROM table1 WHERE sku="' . $sku . '"';
$result = mysql_query($result);
while ($row = mysql_fetch_array($result)) {
echo '<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td><h4>'.$row["sku"].'</h4></td>
<td><h3>'.$row["productname"].'</h3></td>
<td rowspan="2" width="30%"><img src="'.$row["productimg"].'" width="100%" alt="productimg"/></td>
</tr>
<tr>
<td colspan="2" rowspan="2"><p>'.$row["productdesc"].'</p></td>
</tr>
<tr>
<td><a class="button" href="'.$row["producturl"].'">View Product</a> <a class="alert button" href="">No Match</a> <a class="alert button" href="">Match</a></td>
</tr>
</table>';
}
?>
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