使用c#修剪() xml文档中所有xml元素和属性的值

Question

I'm trying to figure out the simplest way to take xml like this:

<Car>
 <Description Model="Ford      ">Blue     </Description>
</Car>

into this:

<Car>
  <Description Model="Ford">Blue</Description>
</Car>

Answer 1

Using LINQ to XML, how about something like:

foreach (var element in doc.Descendants())
{
    foreach (var attribute in element.Attributes())
    {
        attribute.Value = attribute.Value.Trim();
    }
    foreach (var textNode in element.Nodes().OfType<XText>())
    {
        textNode.Value = textNode.Value.Trim();
    }    
}

I think that should work... I don't believe you need to use ToList to avoid disturbing things as you iterate, as you're not changing the structure of the XML document, just the text.

Answer 2

Try this. Don't forget to recurse through your ChildNodes ...

protected void Page_Load(object sender, EventArgs e)
{
    XmlDocument doc = new XmlDocument();
    doc.Load(@"c:\temp\cars.xml");
    Recurse(doc.ChildNodes);
}
private void Recurse(XmlNodeList nodes)
{
    foreach (XmlNode node in nodes)
    {
        if (node.InnerText != null)
            node.InnerText = node.InnerText.Trim();

        if (node.Attributes != null)
        {
            foreach (XmlAttribute att in node.Attributes)
                att.Value = att.Value.Trim();
        }

        Recurse(node.ChildNodes);
    }
}

Answer 3

If you're not using or can't use LINQ to XML then the below worked well for me with XmlDocument

TrimXmlText(xmlDocument.ChildNodes);

private void TrimXmlText(XmlNodeList xmlNodeList)
{
    foreach (XmlNode xmlNode in xmlNodeList)
    {
        if (xmlNode.NodeType == XmlNodeType.Text)
        {
            xmlNode.InnerText = xmlNode.InnerText?.Trim();
        }
        else
        {
            TrimXmlText(xmlNode.ChildNodes);
        }
    }
}